无法使用Python请求上载图像

Question

我在使用python请求上传一些图像时遇到问题。我试图上传照片的网站是myauto。

当我单击它并选择“图像”时，我可以在浏览器的“网络”选项卡中看到此端点上发送的请求：

https://static.my.ge/

这是从浏览器发送的表单数据

要查看完整的来源：

首先，我尝试使用以下脚本发布数据：

image_data = (
    # 'Files[]: (binary)
    ('do', 'Files'),
    ('Func', 'UploadPhotos'),
    ('SiteID', 1),
    ('UserID', 4134977),
    ('IP', 'XX.XX.XX.XX'),
    ('UploadedFiles', 0)
)
# NOTE - we can have multiple `Files[]`
image_urls = tuple()
image_urls += (('Files[]', 'some_image.jpg'),)
response = requests.request(
    method='POST',
    url='https://static.my.ge/',
    data=self.image_data + image_urls,
    headers=headers
)

我正在使用的标题：

headers = {
    'content-type': "multipart/form-data; boundary=----WebKitFormBoundary7MA4YWxkTrZu0gW",
    'Accept-Encoding': "gzip, deflate, br",
    'Accept': "*/*",
    'Connection': "keep-alive",
    'Host': "static.my.ge",
    'Origin': "https://www.myauto.ge",
    'Referer': "https://www.myauto.ge/ka/add",
    'sec-ch-ua': '" Not A;Brand";v="99", "Chromium";v="90", "GoogleChrome";v="90"',
    'sec-ch-ua-mobile': "?0",
    'Sec-Fetch-Dest': "empty",
    'Sec-Fetch-Mode': "cors",
    'Sec-Fetch-Site': "cross-site",
    'User-Agent': "Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/90.0.4430.93 Safari/537.36",
    'cache-control': "no-cache"
}

但我一直得到以下回应：

{'StatusID': 0, 'StatusCode': 0, 'Message': 'Incorrect Func'}

这是期望的输出：

"StatusID": 0,
"StatusCode": 1,
"Message": "Error occurred during the operation",
"Data": {
    "FilesList": [
        "https://static.my.ge/tmp/6db262b3d7a2f9bfd56618640b6deed8_thumbs.jpg"
    ],
    "imgKey": [
        "6db262b3d7a2f9bfd56618640b6deed8"
    ]
}

然后我尝试生成相同的Webkit表单Boundry并将原始字符串传递给数据，但始终得到相同的结果。我还尝试发送图像blob或base64格式，但仍然收到相同的错误

然后我尝试使用postman在这个端点上发送请求，它成功地返回了我所期望的数据。我在正文部分选择了表单数据格式，并通过邮递员上传了文件。然后我尝试查看请求的日志，并尝试从postman复制它并使用python脚本运行，但没有成功，仍然得到相同的错误。最后，我尝试从postman代码生成器复制代码片段，但仍然没有成功。我不明白发生了什么事，也没有办法了

编辑：

以下是邮递员脚本：

url = "https://static.my.ge"

payload = (
    "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
    "form-data; name=\"Files[]\"; filename=\"some_image.jpg\"\r\n"
    "Content-Type: image/jpeg\r\n\r\n\r\n"
    "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
    "form-data; name=\"do\"\r\n\r\nFiles\r\n"
    "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
    "form-data; name=\"SiteID\"\r\n\r\n1\r\n"
    "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
    "form-data; name=\"UserID\"\r\n\r\n1902119\r\n"
    "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
    "form-data; name=\"IP\"\r\n\r\nXX.XX.XX.XX\r\n"
    "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
    "form-data; name=\"UploadedFiles\"\r\n\r\n0\r\n"
    "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
    "form-data; name=\"Func\"\r\n\r\nUploadPhotos\r\n"
    "------WebKitFormBoundary7MA4YWxkTrZu0gW--"
)
response = requests.request("POST", url, data=payload, headers=headers)

此外，我们还发现，这就是图像在请求中的表示方式。不确定如何在python代码中执行相同操作：

更新： 试图修改邮递员生成的脚本：

   payload = (
        "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
        "form-data; name=\"Files[]\"; filename=\"blob\"\r\n"
        "Content-Type: image/jpg\r\n\r\n"
        f"{image}\r\n"
        "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
        "form-data; name=\"do\"\r\n\r\nFiles\r\n"
        "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
        "form-data; name=\"SiteID\"\r\n\r\n1\r\n"
        "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
        "form-data; name=\"UserID\"\r\n\r\n1902119\r\n"
        "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
        "form-data; name=\"IP\"\r\n\r\nXX.XX.XX.XX\r\n"
        "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
        "form-data; name=\"UploadedFiles\"\r\n\r\n0\r\n"
        "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: "
        "form-data; name=\"Func\"\r\n\r\nUploadPhotos\r\n"
        "------WebKitFormBoundary7MA4YWxkTrZu0gW--"
    )

尝试将base64和二进制图像替换为f{"image"}。但从服务器收到新的错误消息，不确定是否有用

object(Exception)#4 (7) {
  ["message":protected]=>
  string(34) "Invalid image file: /tmp/phpFMI89k"
  ["string":"Exception":private]=>
  string(0) ""
  ["code":protected]=>
  int(7)
  ["file":protected]=>
  string(58) "/datastore/web/static.my.ge/htdocs/libs/SimpleImageNew.php"
  ["line":protected]=>
  int(130)
  ["trace":"Exception":private]=>
  array(3) {
    [0]=>
    array(6) {
      ["file"]=>
      string(44) "/datastore/web/static.my.ge/htdocs/index.php"
      ["line"]=>
      int(1300)
      ["function"]=>
      string(8) "fromFile"
      ["class"]=>
      string(14) "SimpleImageNew"
      ["type"]=>
      string(2) "->"
      ["args"]=>
      array(1) {
        [0]=>
        string(14) "/tmp/phpFMI89k"
      }
    }
    [1]=>
    array(6) {
      ["file"]=>
      string(44) "/datastore/web/static.my.ge/htdocs/index.php"
      ["line"]=>
      int(494)
      ["function"]=>
      string(12) "UploadPhotos"
      ["class"]=>
      string(7) "_Static"
      ["type"]=>
      string(2) "->"
      ["args"]=>
      array(0) {
      }
    }
    [2]=>
    array(6) {
      ["file"]=>
      string(44) "/datastore/web/static.my.ge/htdocs/index.php"
      ["line"]=>
      int(3066)
      ["function"]=>
      string(7) "SetFunc"
      ["class"]=>
      string(7) "_Static"
      ["type"]=>
      string(2) "->"
      ["args"]=>
      array(0) {
      }
    }
  }
  ["previous":"Exception":private]=>
  NULL
}

Answer 1

您是否尝试将文件上载到其他api？我会把它上传到一个极简的烧瓶应用程序。以下代码来自flask文档（https://flask.palletsprojects.com/en/1.1.x/patterns/fileuploads/）

只需将UPLOAD_文件夹调整到您计算机上的一个文件夹，然后您就可以尝试向http://127.0.0.1:5000/发送post请求。它应该将文件保存到定义的上载文件夹中。如果这样做有效，您知道您至少在请求方面做了正确的事情

import os
from flask import Flask, flash, request, redirect, url_for
from werkzeug.utils import secure_filename

UPLOAD_FOLDER = '/path/to/uploads/folder'
ALLOWED_EXTENSIONS = {'txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif'}

app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER

def allowed_file(filename):
    return '.' in filename and \
           filename.rsplit('.', 1)[1].lower() in ALLOWED_EXTENSIONS

@app.route('/', methods=['GET', 'POST'])
def upload_file():
    if request.method == 'POST':
        # check if the post request has the file part
        if 'file' not in request.files:
            flash('No file part')
            return redirect(request.url)
        file = request.files['file']
        # if user does not select file, browser also
        # submit an empty part without filename
        if file.filename == '':
            flash('No selected file')
            return redirect(request.url)
        if file and allowed_file(file.filename):
            filename = secure_filename(file.filename)
            file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
            return redirect(url_for('uploaded_file',
                                    filename=filename))
    return '''
    <!doctype html>
    <title>Upload new File</title>
    <h1>Upload new File</h1>
    <form method=post enctype=multipart/form-data>
      <input type=file name=file>
      <input type=submit value=Upload>
    </form>
    '''

if __name__ == "__main__":
    print("hello")
    app.run()