这段代码如下:我的机器人拍了一张照片,一些tf计算机视觉模型计算出目标物体在图片中的起始位置。该信息(x1和x2坐标)被传递到pytorch模型。它应该学会预测正确的运动激活,以便更接近目标。执行移动后,机器人再次拍照,tf cv模型应计算电机激活是否使机器人更接近所需状态(x1位于10,x2坐标位于31)
但是每次运行代码时,pytorch都无法计算梯度
我想知道这是一个数据类型的问题,还是一个更一般的问题:如果不是直接从pytorch网络的输出计算损耗,是否不可能计算梯度
任何帮助和建议都将不胜感激
#define policy model (model to learn a policy for my robot)
import torch
import torch.nn as nn
import torch.nn.functional as F
class policy_gradient_model(nn.Module):
def __init__(self):
super(policy_gradient_model, self).__init__()
self.fc0 = nn.Linear(2, 2)
self.fc1 = nn.Linear(2, 32)
self.fc2 = nn.Linear(32, 64)
self.fc3 = nn.Linear(64,32)
self.fc4 = nn.Linear(32,32)
self.fc5 = nn.Linear(32, 2)
def forward(self,x):
x = self.fc0(x)
x = F.relu(self.fc1(x))
x = F.relu(self.fc2(x))
x = F.relu(self.fc3(x))
x = F.relu(self.fc4(x))
x = F.relu(self.fc5(x))
return x
policy_model = policy_gradient_model().double()
print(policy_model)
optimizer = torch.optim.AdamW(policy_model.parameters(), lr=0.005, betas=(0.9,0.999), eps=1e-08, weight_decay=0.01, amsgrad=False)
#make robot move as predicted by pytorch network (not all code included)
def move(motor_controls):
#define curvature
# motor_controls[0] = sigmoid(motor_controls[0])
activation_left = 1+(motor_controls[0])*99
activation_right = 1+(1- motor_controls[0])*99
print("activation left:", activation_left, ". activation right:",activation_right, ". time:", motor_controls[1]*100)
#start movement
#main
import cv2
import numpy as np
import time
from torch.autograd import Variable
print("start training")
losses=[]
losses_end_of_epoch=[]
number_of_steps_each_epoch=[]
loss_function = nn.MSELoss(reduction='mean')
#each epoch
for epoch in range(2):
count=0
target_reached=False
while target_reached==False:
print("epoch: ", epoch, ". step:", count)
###process and take picture
indices = process_picture()
###binary_network(sliced)=indices as input for policy model
optimizer.zero_grad()
###output: 1 for curvature, 1 for duration of movement
motor_controls = policy_model(Variable(torch.from_numpy(indices))).detach().numpy()
print("NO TANH output for motor: 1)activation left, 2)time ", motor_controls)
motor_controls[0] = np.tanh(motor_controls[0])
motor_controls[1] = np.tanh(motor_controls[1])
print("TANH output for motor: 1)activation left, 2)time ", motor_controls)
###execute suggested action
move(motor_controls)
###take and process picture2 (after movement)
indices = (process_picture())
###loss=(binary_network(picture2) - desired
print("calculate loss")
print("idx", indices, type(torch.tensor(indices)))
# loss = 0
# loss = (indices[0]-10)**2+(indices[1]-31)**2
# loss = loss/2
print("shape of indices", indices.shape)
array=np.zeros((1,2))
array[0]=indices
print(array.shape, type(array))
array2 = torch.ones([1,2])
loss = loss_function(torch.tensor(array).double(), torch.tensor([[10.0,31.0]]).double()).float()
print("loss: ", loss, type(loss), loss.shape)
# array2[0] = loss_function(torch.tensor(array).double(),
torch.tensor([[10.0,31.0]]).double()).float()
losses.append(loss)
#start line causing the error-message (still part of main)
###calculate gradients
loss.backward()
#end line causing the error-message (still part of main)
###apply gradients
optimizer.step()
#Output (so far as intented) (not all included)
#calculate loss
idx [14. 15.] <class 'torch.Tensor'>
shape of indices (2,)
(1, 2) <class 'numpy.ndarray'>
loss: tensor(136.) <class 'torch.Tensor'> torch.Size([])
#Error Message:
Traceback (most recent call last):
File "/home/pi/Desktop/GradientPolicyLearning/PolicyModel.py", line 259, in <module>
array2.backward()
File "/home/pi/.local/lib/python3.7/site-packages/torch/tensor.py", line 134, in backward
torch.autograd.backward(self, gradient, retain_graph, create_graph)
File "/home/pi/.local/lib/python3.7/site-packages/torch/autograd/__init__.py", line 99, in
backward
allow_unreachable=True) # allow_unreachable flag
RuntimeError: element 0 of tensors does not require grad and does not have a grad_fn
如果不直接从PyTorch网络的输出计算损失,则确实不可能计算梯度,因为这样您将无法应用用于优化梯度的链式规则
如果对预测调用
.detach()
,将删除渐变。由于您首先从模型中获取索引,然后尝试支持错误,因此我建议这将保持预测与可反向推进的计算梯度相同。
现在你可以做了
注意,如果预测抛出错误,您可能需要调用预测的两倍
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