Scrapy：选择所有子元素的文本，但返回子元素作为HTML

Question

我正在编写一个Scrapy spider来刮this page，我只需要类为jam_content的元素及其所有子元素的文本。所以理想情况下我应该

CYBERPUNK GAME JAM 2014
CLICK HERE!

这是我的选择器response.css(".jam_content *::text").extract()：

它甚至返回子对象的HTML

['\r\n\r\n\r\n',
 '\r\n',
 'CYBERPUNK GAME JAM 2014',
 '\r\n',
 '\r\n  \r\n  .game_grid .game_cell .game_title a {\r\n    color: #029671;\r\n  }\r\n  \r\n    .game_grid .game_cell .game_author a {\r\n    color: #00aa99;\r\n  }\r\n  \r\n    .game_grid .game_cell .game_genre {\r\n    color: #c5007d;\r\n  }\r\n  \r\n      .game_grid .game_cell .game_platform {\r\n    color: #990088;\r\n  }\r\n  \r\n  \r\n  .add_game_btn {\r\n    background-color: #029671;\r\n    border: 4px solid #c5007d;\r\n    box-shadow: 0 0 0 4px #380024;\r\n    padding: 10px 15px;\r\n    font-size: 18px;\r\n    font-family: \'Lucida Console\';\r\n    color: #00ffcc;\r\n    cursor: pointer;\r\n} \r\n  \r\n
.view_jam .grid_outer {\r\n    border-top:0;\r\n    border-bottom:0;\r\n    background:#000; }\r\n  \r\nbody {\r\n\tbackground-image: url(http://i.imgur.com/ReRqo6t.png);\r\n\tbackground-repeat: repeat-x;\r\n\tbackground-color: #000;\r\n}\r\nbody,td,th {\r\n\tcolor: #0FF;\r\n\tfont-family: "Lucida Console", Monaco, monospace;\r\n}\r\na:link {\r\n\tcolor: #C5007D;\r\n}\r\na:visited {\r\n\tcolor: #C5007D;\r\n}\r\na:hover {\r\n\tcolor: #C5007D;\r\n}\r\na:active {\r\n\tcolor: #C5007D;\r\n}\r\n.mag_not_link {\r\n\tcolor: #C5007D;\r\n\tfont-weight: bold;\r\n}\r\n',
 '\r\n\r\n\r\n\r\n',
 '\r\n  ',
 '\r\n  ',
 'CLICK HERE!',
 '\r\n',
 '\r\n\r\n']

我尝试了另一个response.xpath("./*[@class='jam_content']//text()")，它什么也不返回

我该怎么做

Answer 1

更新选择器以不获取style元素的内容：

response.css(".jam_content *:not(style)::text").extract()

然后，您可以进行列表理解，用.strip()筛选出空白文本项：

my_text = [text for text in response.css(".jam_content *:not(style)::text").extract() if text.strip()]

这将返回：

['CYBERPUNK GAME JAM 2014', 'CLICK HERE!']

然后，您可以简单地将其连接在一起：

print('\n'.join(my_text))