擅长:python、mysql、java
<p>简单地说,您可以迭代矩阵并对每个列表进行切片</p>
<pre><code>matrix = [[3, 5, 7, 9],
[6, 8, 12, 14],
[2, 1, 0, 5],
[7, 8, 9, 10]]
new_matrix=[]
for mat in matrix:
new_matrix.append(mat[:2])
</code></pre>
<p>输出:</p>
<pre><code>[[3, 5], [6, 8], [2, 1], [7, 8]]
</code></pre>