将类从列表解压到modu中

Question

我使用type()动态地定义了几个类，并将它们放在一个列表中。但是，我想让这些类在模块中可用。例如，如果我的模块是factories.py，而我创建的动态类是PersonFactory，那么我可以调用from factories import PersonFactory

这是factories.py中代码的一部分：

factories = []

for name, obj in models:
    factory_name = name + 'Factory' # e.g. PersonFactory
    attrs = assemble_factory_attrs(obj, factory_name)
    f = type(factory_name, (object,), attrs)
    factories.append(f)

# I wanted to "release" the classes into the module definition through `*factories`
# but I get this syntax error: "SyntaxError: can use starred expression only as assignment target"
*factories

谢谢你

Answer 1

您可以将它们添加到模块globals()它将如下所示：

factories = []
module = globals()

for name, obj in models:
    factory_name = name + 'Factory' # e.g. PersonFactory
    attrs = assemble_factory_attrs(obj, factory_name)
    f = type(factory_name, (object,), attrs)
    module[factory_name] = f
    factories.append(f)

现在它们都在模块（全局）范围内，并且在列表factories中