如何在python列表中创建和比较JSON值

2024-05-23 15:19:49 发布

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尝试构建和比较从jsonrestapi提取的项目列表,似乎有一种更简单的方法,然后将整个JSON响应转换为

我有来自restapi的JSON数据,我想从中提取和比较数据对。代码显示了从响应中提取的两个值,但我想重复这样做,只显示尚未返回的值

>>> response = requests.get('http://192.168.2.3:8081/api/session/wifi', auth=('user', 'pass'))
>>> json_response = response.json()
>>> #parse the json and get list of mac and channels
... for each in json_response['aps']:
...     channel = each['channel']
...     mac = each['mac']
...     print channel, mac
...
11 74:83:c2:1a:d2:74
11 18:e8:29:bb:16:39
11 f0:f2:49:0b:9b:e8
6 c0:7c:d1:b8:14:28
6 84:34:97:b4:0f:a1
11 76:83:c2:1a:d2:74
11 f0:f2:49:e2:2c:e8
1 1a:e8:29:9d:1e:63
11 1a:e8:29:9b:16:39
11 1a:e8:29:9d:1f:16
11 18:e8:29:9d:1f:16
1 18:e8:29:9d:1e:63

我希望有一种更简单的方法可以使用JSON请求对象来实现这一点

以下是源JSON:

{
    "aps": [{
            "received": 0,
            "handshake": false,
            "clients": [],
            "vendor": "Ubiquiti Networks Inc.",
            "encryption": "WPA2",
            "hostname": "CoreWireless",
            "authentication": "PSK",
            "wps": {},
            "sent": 1875183,
            "alias": "",
            "mac": "18:e8:29:9d:1e:63",
            "meta": {
                "values": {}
            },
            "frequency": 2412,
            "ipv4": "0.0.0.0",
            "ipv6": "",
            "rssi": -63,
            "first_seen": "2019-09-18T09:56:09.938447-06:00",
            "cipher": "TKIP",
            "channel": 1,
            "last_seen": "2019-09-18T12:45:50.489350663-06:00"
        }, {
            "received": 0,
            "handshake": false,
            "clients": [],
            "vendor": "",
            "encryption": "WPA2",
            "hostname": "<hidden>",
            "authentication": "PSK",
            "wps": {},
            "sent": 0,
            "alias": "",
            "mac": "1a:e8:29:9b:16:39",
            "meta": {
                "values": {}
            },
            "frequency": 2462,
            "ipv4": "0.0.0.0",
            "ipv6": "",
            "rssi": -73,
            "first_seen": "2019-09-18T09:56:12.473447-06:00",
            "cipher": "CCMP",
            "channel": 11,
            "last_seen": "2019-09-18T12:45:49.718002705-06:00"
        }
    ]
}

Tags: and数据方法jsongetresponsemacchannel
2条回答

你能实现如下缓存吗

cache = set()
for each in json_response['aps']:
    channel = each['channel']
    mac = each['mac']
    if (channel, mac) not in cache:
        print channel, mac
        cache.add((channel, mac))

您可以使用set存储唯一元素,并使用下面的一行打印非重复通道、mac对:

print ({(each['channel'], each['mac']) for each in json_response['aps']})

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