尝试构建和比较从jsonrestapi提取的项目列表,似乎有一种更简单的方法,然后将整个JSON响应转换为
我有来自restapi的JSON数据,我想从中提取和比较数据对。代码显示了从响应中提取的两个值,但我想重复这样做,只显示尚未返回的值
>>> response = requests.get('http://192.168.2.3:8081/api/session/wifi', auth=('user', 'pass'))
>>> json_response = response.json()
>>> #parse the json and get list of mac and channels
... for each in json_response['aps']:
... channel = each['channel']
... mac = each['mac']
... print channel, mac
...
11 74:83:c2:1a:d2:74
11 18:e8:29:bb:16:39
11 f0:f2:49:0b:9b:e8
6 c0:7c:d1:b8:14:28
6 84:34:97:b4:0f:a1
11 76:83:c2:1a:d2:74
11 f0:f2:49:e2:2c:e8
1 1a:e8:29:9d:1e:63
11 1a:e8:29:9b:16:39
11 1a:e8:29:9d:1f:16
11 18:e8:29:9d:1f:16
1 18:e8:29:9d:1e:63
我希望有一种更简单的方法可以使用JSON请求对象来实现这一点
以下是源JSON:
{
"aps": [{
"received": 0,
"handshake": false,
"clients": [],
"vendor": "Ubiquiti Networks Inc.",
"encryption": "WPA2",
"hostname": "CoreWireless",
"authentication": "PSK",
"wps": {},
"sent": 1875183,
"alias": "",
"mac": "18:e8:29:9d:1e:63",
"meta": {
"values": {}
},
"frequency": 2412,
"ipv4": "0.0.0.0",
"ipv6": "",
"rssi": -63,
"first_seen": "2019-09-18T09:56:09.938447-06:00",
"cipher": "TKIP",
"channel": 1,
"last_seen": "2019-09-18T12:45:50.489350663-06:00"
}, {
"received": 0,
"handshake": false,
"clients": [],
"vendor": "",
"encryption": "WPA2",
"hostname": "<hidden>",
"authentication": "PSK",
"wps": {},
"sent": 0,
"alias": "",
"mac": "1a:e8:29:9b:16:39",
"meta": {
"values": {}
},
"frequency": 2462,
"ipv4": "0.0.0.0",
"ipv6": "",
"rssi": -73,
"first_seen": "2019-09-18T09:56:12.473447-06:00",
"cipher": "CCMP",
"channel": 11,
"last_seen": "2019-09-18T12:45:49.718002705-06:00"
}
]
}
你能实现如下缓存吗
您可以使用
set
存储唯一元素,并使用下面的一行打印非重复通道、mac对:相关问题 更多 >
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