我正在尝试拆分一个json文件(python列表),如下所示:
liftOver = {"/
Contig1863": [["ref0000283e3", "-", 3681], ["ref0000283e3_ref0000283e5", "-", 7468]], "/
Contig1862": [["ref0001167e3_ref0001167e5", "-", 13438]], "/
Contig1861": [["ref0001923e3_ref0001923e5", "-", 13221]], "/
Contig1860": [["ref0000920e3", "+", 769], ["ref0000920e3_ref0000920e5", "-", 6640]], "/
Contig1867": [["ref0001036e3_ref0001036e5", "-", 14133]], "/
Contig1866": [["ref0000256e3_ref0000256e5", "+", 11744]], "/
Contig1865": [["ref0001172e3_ref0001172e5", "+", 8445]], "/
Contig1864": [["ref0000694e3_ref0000694e5", "-", 26308]], "/
Contig1869": [["ref0001325e5", "-", 396], ["ref0001325e3_ref0001325e5", "+", 17739]], "/
Contig1868": [["ref0001621e5", "+", 3742], ["ref0001621e3_ref0001621e5", "+", 14315]], " }
我只需要打印第一个键值(即ref0000*),包括键(Contig*),然后用(''''')分割这些键值。有人有什么想法吗?对我来说似乎不管用。我的代码是:
for key, value in liftOver.iteritems():
lift_split=[liftOver.split("[_]") for value in liftOver.values()]
print(lift_split)
AttributeError:“dict”对象没有属性“split”
上述输出:
我不确定我是否正确理解了你的问题。你知道吗
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