我试图解析列表k
,并使用字典中列表k的相应值k_dict
来创建另一个字典firmware_versions_for_all_chip_revs_dict
,我有当前输出和预期输出来理解用例吗?我哪里出错了,怎么解决?你知道吗
k = ['C-4350__s-C5','C-4345__s-B1','C-4350__s-C2','C-43452__s-A3','C-4355__s-C0','C-4355__s-C1','C-4355__s-B3']
count = 0
firmware_versions_for_all_chip_revs_dict = {}
k_dict = {'C-4350__s-C5':True,'C-4345__s-B1':True,'C-4350__s-C2':False,'C-43452__s-A3':True,'C-4355__s-C0':False,'C-4355__s-C1':True,'C-4355__s-B3':True}
for value in k:
print value
chip = re.search(r'([0-9]+)',value,flags=re.IGNORECASE).group()
all_trx_versions_same = k_dict[value]
if count == 0:
originalchip = chip
if chip.strip() == originalchip.strip():
print 'Inside chip equal to'
#all_trx_versions_list.append(all_trx_versions_same)
try:
firmware_versions_for_all_chip_revs_dict[originalchip].append(all_trx_versions_same)
count += 1
except:
firmware_versions_for_all_chip_revs_dict[originalchip] = all_trx_versions_same
originalchip = chip
count += 1
elif chip.strip() != originalchip.strip():
print 'Inside chip not equal to '
#firmware_versions_for_all_chip_revs_dict[originalchip] = all_trx_versions_list
#all_trx_versions_list = []
originalchip = chip
count +=1
print firmware_versions_for_all_chip_revs_dict
当前输出:-你知道吗
{'4355': True, '4350': True}
预期输出:-你知道吗
{'4355': '[False,True,True]','4350': '[True,False]','4345':'[True]','43452',['True']}
这可能会帮助您:
输出:
只需将
output
变量的名称替换为firmware_versions_for_all_chip_revs_dict
。你知道吗相关问题 更多 >
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