使用for循环组合列表？

Question

我这里有个密码：

print('Hello Alex! Please tell me how many different shells you collected.')
pukaAlex = int(input('Puka: '))
coneAlex = int(input('Cone: '))
driftwoodAlex = int(input('Driftwood: '))
seaglassAlex = int(input('Sea Glass: '))
starfishAlex = int(input('Starfish: '))
lstAlex = [pukaAlex, coneAlex, driftwoodAlex, seaglassAlex, starfishAlex]

print('Hello Bay! Please tell me how many different shells you collected.')
pukaBay = int(input('Puka: '))
coneBay = int(input('Cone: '))
driftwoodBay = int(input('Driftwood: '))
seaglassBay = int(input('Sea Glass: '))
starfishBay = int(input('Starfish: '))
lstBay = [pukaBay, coneBay, driftwoodBay, seaglassBay, starfishBay]

lstAlexTwo = [('Puka', pukaAlex), ('Cone', coneAlex),
              ('Driftwood', driftwoodAlex), ('Sea Glass', seaglassAlex),
              ('Starfish', starfishAlex)]
lstBayTwo = [('Puka', pukaBay), ('Cones', coneBay),
             ('Driftwood', driftwoodBay), ('Sea Glass', seaglassBay),
             ('Starfish', starfishBay)]

print('Alex\'s List: ', lstAlexTwo)
print('Bay\'s List: ', lstBayTwo)

我知道我有其他组合列表的选项，但是我不完全确定如何将Alex和Bay列表中的Pukas和cone的数量与for循环组合起来，从而创建一个新的列表。你知道吗

我知道我可以使用+字符来添加这两个字符

样本输出：

[('Puka', 52), ('Cone', 21)] 

假设收集的普卡犬总数为52只，球果为21只。你知道吗

Answer 1

下面是如何组合这些值。然后你可以做你在最后做的事情，把它们和一个新列表中的字符串组合起来。你知道吗

newList = []
for i in range(len(lstBay)):
    newList.append(lstBay[i] + lstAlex[i])

Answer 2

试试这个：

new_list = [(name, val1+val2) for (name, val1), (_, val2) in zip(lstAlexTwo, lstBayTwo)]