布尔条件的读数为True，但while循环仍然没有中断

Question

由于某些原因，当条件满足时，while循环没有中断。while循环应该检查玩家的输入，以填充tic-tac趾板，直到变量“win”为真。你知道吗

一旦电路板反映了tic-tac-toe的一个获胜条件，它就会将变量“win”赋值为True，并反过来跳出循环。你知道吗

出于某种原因，循环没有中断，但是变量“win”的读数仍然是真的。你知道吗

有人能解释为什么循环没有中断吗？我尝试将while循环的条件重写为“while win==False”，但这似乎也不能解决问题。你知道吗

我已经包括了一些我正在使用的函数，并在旁边用注释解释了一些更简单的函数。你知道吗

我正在使用复制所有这些都是在网上完成的，而不是在本地机器上的程序上，所以我认为这可能也是问题的一部分。你知道吗

import os
board = ["#"," "," "," "," "," "," "," "," "," "]

def determine_win(marker):
    # Winning Patterns:
    # (1,2,3), (4,5,6), (7,8,9), (1,4,7), (2,5,8), (3,6,9), (3,5,7), (1,5,9)   

    if board[1]== board[2]==board[3]==marker:
        return True    
    elif board[4]== board[5]==board[6]==marker:
        return True    
    elif board[7]== board[8]==board[9]==marker:
        return True    
    elif board[1]== board[4]==board[7]==marker:
        return True    
    elif board[2]== board[5]==board[8]==marker:
        return True    
    elif board[3]== board[6]==board[9]==marker:
        return True    
    elif board[3]== board[5]==board[7]==marker:
        return True 
    elif board[1]== board[5]==board[9]==marker:
        return True       
    else:
        return False

player1 = xo() # A Function that takes user input either "X" or O"
if player1 == "X":
    player2 = "O"
else:
    player2 = "X"

win = False
while not win:
    display_board(board) # display_baord(board) takes the list "board" and uses it as input to display the tic tac toe board to the screen. 
    print("\nPlayer 1")
    board[player_turn()] = player1

    win = determine_win(player1)
    print(win) # used to verify if win is changing
    input()    # used to pause the screen for troubleshooting

    display_board(board)
    print("\nPlayer 2")
    board[player_turn()] = player2

    win = determine_win(player2)
    print(win) # used to verify if win is changing
    input()    # used to pause the screen for troubleshooting

print("Win Declared")

Answer 1

正如注释所说，原因是while只在完成循环的整个迭代时检查win的条件。我更喜欢以下方法使代码更整洁：

# win = False <  you don't need this now
while True:
    display_board(board) # display_baord(board) takes the list "board" and uses it as input to display the tic tac toe board to the screen. 
    print("\nPlayer 1")
    board[player_turn()] = player1

    if determine_win(player1):
        print("Player 1 won")
        break # break out of the loop

    display_board(board)
    print("\nPlayer 2")
    board[player_turn()] = player2

    if determine_win(player2):
        print("Player 2 won")
        break # break out of the loop

Answer 2

if not determine_win(player1):
  display_board(board)
  print("\nPlayer 2")
  board[player_turn()] = player2

  win = determine_win(player2)
  # player 2 wins
else:
  # player 1 wins
  win = True

用这样的东西。这与@jasonharper和@Idlehands的回答相同