我正在使用SQLAlchemy动态生成PL/SQL,使用compile
并设置dialect
和compile_kwargs
参数(例如,使用str(ins.compile(dialect=oracle.dialect(), compile_kwargs={'literal_binds': True}))
),这很好,只是输出没有用最漂亮的SQL语句格式化。
例如,我的一个输出如下所示:
INSERT INTO my_table (a, b, c) SELECT my_table2.d, bar.e, bar.f
FROM my_table2 JOIN (SELECT my_table3.e AS e, max(my_table3.f) AS f, count(my_table3.g) AS g
FROM my_table3
WHERE my_table3.h = 'foo' GROUP BY my_table3.e
HAVING count(my_table3.g) = 1) bar ON my_table2.g = bar.g
相反,我希望这样打印出来:
INSERT INTO my _table (a, b c)
SELECT my_table2.d, bar.e, bar.f
FROM my_table2 JOIN (
SELECT my_table3.e, max(my_table3.f), count(my_table3.g)
FROM my_table3
WHERE my_table3.h = 'foo'
GROUP BY my_table3.e
HAVING count(my_table3.g) = 1
) bar ON my_table2.g = bar.g
如何让SQLAlchemy漂亮地打印SQL语句?
要复制:
from sqlalchemy import table, column, String, Numeric, func, select from sqlalchemy.dialects import oracle my_table = table('my_table', column('a', String), column('b', String), column('c', String)) my_table2 = table('my_table2', column('d', String), column('g', String)) my_table3 = table('my_table3', column('d', String), column('e', String), column('f', Numeric), column('g', String), column('h', String)) inner_sel = select([my_table3.c.e, func.max(my_table3.c.f).label('f'), func.count(my_table3.c.g).label('g')]).where(my_table3.c.h=='foo').group_by(my_table3.c.e).having(func.count(my_table3.c.g)==1).alias('bar') outer_sel = select([my_table2.c.d, inner_sel.c.e, inner_sel.c.f]).select_from(my_table2.join(inner_sel, my_table2.c.g==inner_sel.c.g)) ins = my_table.insert().from_select([my_table.c.a, my_table.c.b, my_table.c.c], outer_sel) print ins.compile(dialect=oracle.dialect(), compile_kwargs={'literal_binds': True})
目前没有回答
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