多亏了Django文档和类似问题的堆栈溢出,我才设法解决了这个问题,但我似乎无法使用歌曲.音频作为我的html的<source>
标记中的src
。你知道吗
显示带有可播放音频文件的歌曲列表。这是从admin/页面上传的。你知道吗
当我检查元素时,<source>
的src
属性似乎成功地指向音频文件,但它不会将其作为浏览器中实际可播放的“东西”加载。你知道吗
在Django runserver控制台中,当单击音频播放器的“播放”按钮时,输出为nothing,但当页面加载时,输出为"GET /songs/media/song_qW9qTXh.mp3 HTTP/1.1" 404 2715
。将媒体目录移动到songs/目录,输出仍然是相同的。你知道吗
检查以下代码的输出:
song-viewer/
| media/
| | song1.mp3
| | song1_w784FH21.mp3
| | song2.mp3
| | song2_r8JJfq0.mp3
|
| song-viewer/
| | __init__.py
| | settings.py
| | urls.py
| | views.py
|
| songs/
| | migrations/
| | templates/
| | | songs/
| | | | song_list.html
| | __init__.pyt
| | admin.py
| | apps.py
| | forms.py
| | models.py
| | urls.py
| | views.py
|
| static/
| | styles.css
|
| templates/
| | base_layout.html
|
| manage.py
| README.md
| requirements.txt
STATIC_URL = '/static/'
STATICFILES_DIRS = [
os.path.join(BASE_DIR,'static'),
]
STATIC_ROOT = ''
"""
The above static works fine (am able to link CSS successfully).
However, the below does not. I have shotgunned several different
methods of doing this, including setting MEDIA_ROOT = os.path.join(BASE_DIR, ''), and hiding MEDIA_ROOT
"""
MEDIA_ROOT = ''
MEDIA_URL='/media/'
from django.contrib import admin
from django.urls import path, include
from . import views
from django.contrib.staticfiles.urls import staticfiles_urlpatterns
urlpatterns = [
path('admin/', admin.site.urls),
path('songs/', include('songs.urls')),
path('', views.homepage)
]
urlpatterns += staticfiles_urlpatterns()
from django.http import HttpResponse
from django.shortcuts import render
def homepage(request):
# return HttpResponse('Hello from Home!')
return render(request, 'homepage.html')
{% extends 'base_layout.html' %}
{% block content %}
<h1>Song List</h1>
<div class="songs-container">
{% for song in songs %}
<div class="song">
<h2><a href="{% url 'songs:detail' slug=song.slug %}">{{ song.title }}</a></h2>
<p>{{ song.snippet }}</p>
<p>{{ song.date }}</p>
<audio controls>
<source src="{{ song.audio }}" type="audio/mpeg" >
<!-- <source src="{{ song.audio }}" type="audio/mpeg" > NOTE: This gives same output-->
</audio>
{{ song.audio }}
</div>
{% endfor %}
</div>
{% endblock %}
from django import forms
class DocumentForm(forms.Form):
docfile = forms.FileField(
label='Select an audio file',
help_text='Must be mp3 format'
)
from django.db import models
class Song(models.Model):
title = models.CharField(max_length=50)
slug = models.SlugField()
desc = models.TextField()
date = models.DateTimeField(auto_now_add=True)
audio = models.FileField(upload_to='media/')
def __str__(self):
return self.title
def snippet(self):
return self.desc[:50] + ' ...'
from django.urls import path
from . import views
app_name = 'songs'
urlpatterns = [
path('', views.song_list, name="list"),
path('<slug>/', views.song_detail, name="detail")
]
from django.shortcuts import render
from django.template import RequestContext
from django.http import HttpResponse, HttpResponseRedirect
from django.urls import reverse
from .models import Song
from .forms import DocumentForm
def song_list(request):
if request.method == 'POST':
form = DocumentForm(request.POST, request.FILES)
if form.is_valid():
newdoc = Song(docfile = request.FILES['docfile'])
newdoc.save()
return HttpResponseRedirect(reverse('song_list'))
else:
form = DocumentForm()
songs_data = Song.objects.all().order_by('date')
return render(request, 'songs/song_list.html', {'songs': songs_data, 'form': form})
def song_detail(request, slug):
return HttpResponse(slug)
我假设您正在开发服务器上运行。您可以使用django.views.static文件.serve()视图。你知道吗
歌曲查看器/设置.py
歌曲查看器/网址.py
引用:https://docs.djangoproject.com/en/2.2/howto/static-files/#serving-files-uploaded-by-a-user-during-development
相关问题 更多 >
编程相关推荐