如何重试urllib2.urlopen n次

2 投票
1 回答
985 浏览
提问于 2025-04-18 05:53

我正在尝试实现一个装饰器,用来重复尝试打开一个网址 n 次。可是我这个装饰器一直没法正常工作。当我运行它的时候,出现了以下错误信息:

追踪信息(最近的调用在最前面):

文件 "F:\retry\dec_class.py",第 60 行,在

x.getURLdata('127.0.0.1')

类型错误:'NoneType' 对象不可调用

有没有人能帮我一下呢?

import serial, urllib2, time
from functools import wraps

import xml.etree.cElementTree as ET
from xml.etree.cElementTree import parse

class Retry(object):

    default_exceptions = (Exception)
    def __init__(self, tries, exceptions=None, delay=0):

        self.tries = tries
        if exceptions is None:
            exceptions = Retry.default_exceptions
        self.exceptions = exceptions
        self.delay = delay

    def __call__(self, f):
        def fn(*args, **kwargs):
            tried = 0
            exception = None

            while tried <= self.tries:
                try:
                    return f(*args, **kwargs)
                except self.exceptions, e:
                    print "Retry, exception: "+str(e)
                    time.sleep(self.delay)
                tried += 1
                exception = e
                #if no success after tries, raise last exception
                raise exception
            return fn 


class getURL(object):

    @Retry(2 )
    def getURLdata(self, IPaddress):

        try:
            f = urllib2.urlopen(''.join(['http://', IPaddress]))
            f = ET.parse(f)

            return f

        except IOError, err:
            print("L112 IOError is %s" %err)
        except urllib2.URLError, err:
            print("L114 urllib2.URLError is %s" %err)
        except urllib2.HTTPError, err:
            print("L116 urllib2.HTTPError is %s" %err)
        except Exception, err :
            print("L118 Exception is %s" %err)


x = getURL()

x.getURLdata('127.0.0.1')

1 个回答

1

你的 __call__ 方法没有返回 fn。相反,它默认返回的是 None,所以 getURLdata 就被绑定到了 None 上。

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