从C#客户端向Python服务器发送HTTP POST请求时出错

1 投票
1 回答
1149 浏览
提问于 2025-04-18 05:46

我刚开始学习客户端和服务器的编程(特别是对Python服务器编程没有经验)。我想把一些数据发送到一个使用cherry.py HTTP框架的Python服务器。下面的代码展示了服务器的实现。

import cherrypy
from cherrypy import request

class test:
    @cherrypy.expose
    def index(self):
        print request.params['port']
        return "Done";


if __name__ == "__main__":
    cherrypy.config.update( {'server.socket_host':"0.0.0.0", 'server.socket_port':8181 } )
    cherrypy.quickstart(test())  

我需要用C#客户端发送一个POST类型的请求。这里是我用来发送数据的方法。

    private void applicationOn()
    {

        using (var client = new WebClient())
        {
            var values = new NameValueCollection();
            values["port"] = "hello";

            var ret = client.UploadValues("http://localhost:8181/", "POST", values);
            MessageBox.Show(Encoding.ASCII.GetString(ret));
        }
    }

虽然这个客户端程序在和PHP配合时运行得很好,但在和Python配合时却不行。当我尝试发送请求时,它给我返回了这个错误:

“远程服务器返回了一个错误:(400) 错误的请求。”这是错误的详细信息。

    System.Net.WebException was unhandled
      HResult=-2146233079
      Message=The remote server returned an error: (400) Bad Request.
      Source=System
      StackTrace:
           at System.Net.WebClient.UploadValues(Uri address, String method, NameValueCollection data)
           at System.Net.WebClient.UploadValues(String address, String method, NameValueCollection data)
           at HTTP_Client.Form1.applicationOn() in c:\Users\pusalk\Documents\Visual Studio 2012\Projects\HTTP Client\HTTP Client\Form1.cs:line 125
           at HTTP_Client.Form1.button1_Click(Object sender, EventArgs e) in c:\Users\pusalk\Documents\Visual Studio 2012\Projects\HTTP Client\HTTP Client\Form1.cs:line 29
           at System.Windows.Forms.Control.OnClick(EventArgs e)
           at System.Windows.Forms.Button.OnClick(EventArgs e)
           at System.Windows.Forms.Button.OnMouseUp(MouseEventArgs mevent)
           at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks)
           at System.Windows.Forms.Control.WndProc(Message& m)
           at System.Windows.Forms.ButtonBase.WndProc(Message& m)
           at System.Windows.Forms.Button.WndProc(Message& m)
           at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)
           at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m)
           at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)
           at System.Windows.Forms.UnsafeNativeMethods.DispatchMessageW(MSG& msg)
           at System.Windows.Forms.Application.ComponentManager.System.Windows.Forms.UnsafeNativeMethods.IMsoComponentManager.FPushMessageLoop(IntPtr dwComponentID, Int32 reason, Int32 pvLoopData)
           at System.Windows.Forms.Application.ThreadContext.RunMessageLoopInner(Int32 reason, ApplicationContext context)
           at System.Windows.Forms.Application.ThreadContext.RunMessageLoop(Int32 reason, ApplicationContext context)
           at System.Windows.Forms.Application.Run(Form mainForm)
           at HTTP_Client.Program.Main() in c:\Users\pusalk\Documents\Visual Studio 2012\Projects\HTTP Client\HTTP Client\Program.cs:line 19
           at System.AppDomain._nExecuteAssembly(RuntimeAssembly assembly, String[] args)
           at System.AppDomain.ExecuteAssembly(String assemblyFile, Evidence assemblySecurity, String[] args)
           at Microsoft.VisualStudio.HostingProcess.HostProc.RunUsersAssembly()
           at System.Threading.ThreadHelper.ThreadStart_Context(Object state)
           at System.Threading.ExecutionContext.RunInternal(ExecutionContext executionContext, ContextCallback callback, Object state, Boolean preserveSyncCtx)
           at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state, Boolean preserveSyncCtx)
           at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state)
           at System.Threading.ThreadHelper.ThreadStart()
      InnerException: 

请帮我解决这个问题。

1 个回答

1

CherryPy的处理器不需要任何参数,你可以试试这样:

import cherrypy
from cherrypy import request

class test:
    @cherrypy.expose
    def index(self, **params):
        # all the request parametes goes into the params dictionary.
        # in case that no port is defined return None
        print params.get('port', None) 
        return "Done";


if __name__ == "__main__":
    cherrypy.config.update( {'server.socket_host':"0.0.0.0",
                             'server.socket_port':8181 })
    cherrypy.quickstart(test())  

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