在Django模板中如何判断request.user是否在与用户相关的对象列表中?
我有一个Django模型,长得像这样:
from django.contrib.auth.models import User
class Cohort(models.Model) :
cohort_name = models.CharField(max_length=64, primary_key=True)
cohort_description = models.TextField(null=False)
creation_date = models.DateTimeField(default=now)
class CohortMembers(models.Model) :
cohort = models.ForeignKey(Cohort)
member = models.ForeignKey(User)
creation_date = models.DateTimeField(default=now)
你可以看到,Cohorts(小组)和Users(用户)之间是多对多的关系。
在一个模板中,我列出了小组,像这样(简化一下让你明白):
{% for cohort in object_list %}
<a href="./{{ cohort.cohort_name }}/">{{ cohort.cohort_name }}</a>
<!-- list all members of the cohort -->
{% for cohortmember in cohort.cohortmembers_set.all %}
{% if request.user.username == cohortmember.member.username %}
<!-- the user is a member of the cohort, provide a delete button -->
<button>Leave cohort</button>
{% else %}
Some other user called {{ cohortmember.member.username }} is a member.
{% endif %}
{% endfor %}
{% endfor %}
我需要做的是,给用户提供一个按钮,让他们可以在还不是小组成员的情况下加入这个小组。在最简单的Python代码中,你可能会这样做:
# clearly some better python would be to use a django model query, rather
# than iterate over the members, but this encapsulates the basic logic
is_member = False
for cohortmember in cohort.cohortmembers_set.all:
if request.user == cohortmember.member:
is_member = True
if is_member :
# a leave button
else:
# a join button
我能在Django的模板语言中做到这些吗?还是说我必须把这样的代码放到View类里面去?
1 个回答
0
我找到的唯一真正有效的方法是结合操作CohortView和一些简单的模板编程。
我把问题换了个角度:不是问“这个用户是不是那个组的成员?”而是问“这个组在用户的会员列表里吗?”这样简单明了。
在CohortListView的get_context_data中如下:
def get_context_data(self, **kwargs) :
context = super(CohortListView, self).get_context_data(**kwargs)
memberships = CohortMembers.objects.filter(member=self.request.user)
cohorts = []
for membership in memberships:
cohorts.append(membership.cohort)
context['memberships'] = cohorts
return context
注意,我放弃了多对多的对象,而是直接在上下文中存储用户所加入的组的列表。
然后,在模板中:
{% for cohort in object_list %}
{% if cohort in memberships %}
<!-- leave button -->
{% else %}
<!-- join button -->
{% endif %}
{% endfor %}