Python对象中数据字段的访问控制

1 投票
1 回答
667 浏览
提问于 2025-04-18 00:59

在下面的代码中,我有一个对象,这个对象有两个字段:一个字典和一个聚合器。聚合器的目的是在 O(1) 的时间内计算字典值的总和。
我想使用属性来控制对这些字段的访问,但字典的设置方法从来没有被调用过:

class C:
    def __init__(self):
        self._p = dict()
        self._sum_of_p_values = 0

    def get_p(self):
        print('getting p')
        return self._p
    def set_p(self, v):
        print('setting p')
        self._p = v
        print('updating the sum')
        self._sum_of_p_values = sum(self._p.values())
    def get_sum_of_values(self):
        return self._sum_of_p_values
    p = property(get_p, set_p, None, None)
    sum_of_values = property(get_sum_of_values, None, None, None) #read-only property

c = C()
c.p['a'] = 1 #value created, expect to update the aggregator
c.p['b'] = 2.14 #value created, expect to update the aggregator
# I want c.sum_of_values to be 3.14
print(c.sum_of_values)

这是上面代码的输出:

getting p
getting p
0

实现我的目标的最佳方法是什么?

1 个回答

0

你直接在设置属性,而不是使用你自己的设置方法。试试这个:

class C:
    def __init__(self):
        self._p = dict()
        self._sum_of_p_values = 0

    def get_p(self):
        print('getting p')
        return self._p
    def set_p(self, k, v):
        print('setting p')
        self._p[k] = v
        print('updating the sum')
        self._sum_of_p_values = sum(self._p.values())
    def get_sum_of_values(self):
        return self._sum_of_p_values
    p = property(get_p, set_p, None, None)
    sum_of_values = property(get_sum_of_values, None, None, None) #read-only property

c = C()

c.set_p('a', 1)  #value created, expect to update the aggregator
c.set_p('b', 2.14) #value created, expect to update the aggregator
# I want c.sum_of_values to be 3.14
print(c.sum_of_values)

如果你不想直接调用你的设置方法,可以用这种方法:

https://stackoverflow.com/a/5021107/2011147

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