关于消除字数中的空白空间

Question

我正在处理一段文字。我需要把这段文字里的单词按字母顺序排列，然后再按出现频率的倒序排列。可是我发现我的单词计数功能在排序的时候也把空格算进去了。我做了一些修改，但它还是会把空字符串算上。我在想有没有其他方法可以做到这一点。我的代码是：

def build_map( in_file, word_map ):

    for line in in_file:

        # Splits each line at blank space and turns it into
        # a list.
        word_list = line.split()

        for word in word_list:
            if word!='':

                # Within the word_list, we are stripping empty space
                # on both sides of each word and also stripping any
                # punctuation on both side of each word in the list.
                # Then, it turns each word to the lower case to avoid
                # counting 'THE' and 'the' as two different words.
                word = word.strip().strip(string.punctuation).lower()#program revised
                add_word( word_map, word )

Answer 1

要从一个字符串列表中筛选出空字符串，我会使用：

my_list = filter(None, my_list)

Answer 2

也许你在找的是 str.isspace() 这个方法。

Answer 3

这段话的意思是，这样做可以帮助你朝着正确的方向前进。你需要对数据进行处理，可能需要去掉句号和冒号，而且你可能还想把所有字母都变成小写。

passage = '''I am dealing with a passage. I am required to sort the words in the passage alphabetically and then sort them by reverse frequency. When my word count function sorts the passage, it counts empty space too. I did some modification and it still counts the empty spaces. I am wondering if there is any other way to do it. My codes are:'''

words = set(passage.split())

alpha_sort = sorted(words, key=str.lower)

frequency_sort = sorted(words, key=passage.count, reverse=True)

Answer 4

不要使用：

if word!='':

你应该使用：

if word.strip()!='':

因为第一个方法是检查字符串是否为空，而你其实想要去掉那些不是空的字符串中的空格。把只有空格的字符串去掉空格后，就变成了空字符串。