在pandas透视表中重新排序列

5 投票
1 回答
3763 浏览
提问于 2025-04-17 21:11

我有一个使用pivot_table方法创建的pandas数据框,结构如下:

import numpy as np
import pandas 

datadict = {
 ('Imps', '10day avg'): {'All': '17,617,872', 'Crossnet': np.nan, 'N/A': '17,617,872'},
 ('Imps', '30day avg'): {'All': '17,302,111', 'Crossnet': '110','N/A': '18,212,742'},
 ('Imps', '3day avg'): {'All': '8,029,438', 'Crossnet': '116', 'N/A': '8,430,904'},
 ('Imps', 'All'): {'All': '14,156,666', 'Crossnet': '113', 'N/A': '14,644,823'},
 ('Spend', '10day avg'): {'All': '$439', 'Crossnet': np.nan, 'N/A': '$439'},
 ('Spend', '30day avg'): {'All': '$468', 'Crossnet': '$0', 'N/A': '$492'},
 ('Spend', '3day avg'): {'All': '$209', 'Crossnet': '$0', 'N/A': '$219'},
 ('Spend', 'All'): {'All': '$368', 'Crossnet': '$0', 'N/A': '$381'}
}
df = pandas.DataFrame.from_dict(datadict)
df.columns = pandas.MultiIndex.from_tuples(df.columns)

我尝试用下面两种方法重新排列“Spend”和“Imps”下的嵌套列,想要按照新的顺序来排列,但无论怎么做,顺序都没有改变,也没有出现错误:

df['Spend']=df['Spend'].reindex_axis(['3day avg','10day avg','30day avg','All'],axis=1)
df['Spend']=df['Spend'][['3day avg','10day avg','30day avg','All']]

1 个回答

5

一种方法是创建一个多重索引,然后根据这个索引重新排列数据:

In [11]: mi = pd.MultiIndex.from_product([['Imps', 'Spend'], ['3day avg','10day avg','30day avg','All']])

In [12]: df.reindex_axis(mi, 1)
Out[12]: 
               Imps                                        Spend                          
           3day avg   10day avg   30day avg         All 3day avg 10day avg 30day avg   All
All       8,029,438  17,617,872  17,302,111  14,156,666     $209      $439      $468  $368
Crossnet        116         NaN         110         113       $0       NaN        $0    $0
N/A       8,430,904  17,617,872  18,212,742  14,644,823     $219      $439      $492  $381

注意:MultiIndex.from_product是在0.13版本中新增的,如果你使用的pandas版本比这个旧,可以使用pd.MultiIndex.from_tuples(list(itertools.product(..)))

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