如何通过BaseHTTPServer在Python中正确向Ajax返回数据和HTTP响应
我有一个用Python写的非常简单的网页服务器。它在8012端口上监听，我该如何让它通过ajax发送一个简单的“Hello World”网页呢？或者有没有其他方法可以接收返回的html数据？
#Copyright Jon Berg , turtlemeat.com
import string,cgi,time
from os import curdir, sep
from BaseHTTPServer import BaseHTTPRequestHandler, HTTPServer
import MySQLdb
from lxml import etree
from lxml.builder import E as buildE
import urllib
global db, cnn
class MyHandler(BaseHTTPRequestHandler):
def do_GET(self):
global cnn, sql
module_name = "UMESSAGE WEBSERVER"
#parse path data
val = self.path.split('/')
type = val[1]
#val_rna = val[2]
#val_imsi = val[3]
if type == 'test':
self.send_response(202, "Processing...")
self.send_header('Content-type', 'xml')
self.end_headers()
self.wfile.write("testing")
print "test"
else:
err = self.wfile.write("Cannot GET "+self.path)
print "else"
self.send_response(200, "else")
self.send_header('Content-type', 'xml')
self.end_headers()
self.wfile.write("else")
def do_POST(self):
global rootnode
try:
ctype, pdict = cgi.parse_header(self.headers.getheader('content-type'))
if ctype == 'multipart/form-data':
query=cgi.parse_multipart(self.rfile, pdict)
self.send_response(301)
self.end_headers()
upfilecontent = query.get('upfile')
print "filecontent", upfilecontent[0]
self.wfile.write("<HTML>POST OK.<BR><BR>");
self.wfile.write(upfilecontent[0]);
except :
pass
def main():
try:
server = HTTPServer(('', 8012), MyHandler)
print 'started httpserver...'
server.serve_forever()
except KeyboardInterrupt:
print '^C received, shutting down server'
server.socket.close()
if __name__ == '__main__':
main()
html/ajax
$.ajax({
url:"http://192.xxx.x.x/test",
type: "POST",
success:function(result){
alert(result);
}});
1 个回答
0
一旦你从服务器得到了响应，结果会保存在一个叫做result的地方。你可以把这个结果放到一个div元素里。
举个例子：
$.ajax({
type: "POST",
url: "/some_url",
data: put-some-data,
success: function(msg){
$("#data").html(msg)
}
})
});
HTML:
<div id="data"></div>