python 3.2-使用字典为字母赋值并计算.txt文件中单词的字母总和

Question

在Python 3.2中，我想用字典来给字母表中的每个字母分配一个值。这个规则是：'a'=1，'b'=2，'c'=3……'z'=26。我有一个叫做words.txt的文件，里面有一长串单词。这些单词都是以大写字母开头的，但我的值只针对小写字母。

总之，我需要给每个单词分配一个值，这个值是它的字母转换成小写后对应的值的总和。

我还知道如何找出列表中有多少个单词的总值是137的整数倍？不过，我对如何让Python读取这个.txt文件感到很困惑。

任何帮助都很欢迎！谢谢！

这是我目前写的代码：

d = {'a':1,'b':2,'c':3,'d':4,'e':5,'f':6,'g':7,'h':8,'i':9,'j':10,'k':11,'l':12,'m':13,'n':14,'o':15,'p':16,'q':17,'r':18,'s':19,'t':20,'u':21,'v':21,'w':23,'x':24,'y':25,'z':26}

find = open("words.txt")
[x.lower() for x in ["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"]]
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']


def num_multiple():  

  for line in find:
    if line.find("word % 137 == 0") == -1:
    return line
   else:
        word = line.strip()

print(num_multiple)
print(len(num_multiple))

Answer 1

你有没有想过用ord()和chr()这两个函数来获取字母的ASCII值呢？

with open('words.txt')as word_file:
    high_score = 0
    for word in word_file:
        word = word.strip()
    value = 0
    for letter in word:
        value += ord(letter) % 97
    if value % 137 == 0:
        high_score += 1
    print('Number of words with values that are a multiple of 137 {}'.format(high_score))

我知道这和你之前的回答没有什么不同，但如果你的字典非常大，这样做可能会占用更少的内存。而且，能够把字符转换成ASCII值再转换回来，可以让你做一些很酷的事情，特别是在加密方面。

Answer 2

我看到这里有几个问题。首先，你使用了 find 来查找字面意思的字符串 "word % 137 == 0"，而不是计算的结果。

这里有一些可以简化你代码的内容：

values_of_words = [] # all the values for words

with open('words.txt') as the_file:
   for word in the_file:
       word = word.strip() # removes \n from the word
       values = [] # we will store letter values for each word
       for letter in word:
          # convert each letter to lowercase
          letter_lower = letter.lower()

          # find the score and add it to values
          values.append(d[letter_lower])

       # For each word, add up the values for each letter
       # and store them in the list
       values_of_words.append(sum(values))

count = 0
for value in values_of_words:
    if value % 137 == 0:
       count += 1

print("Number of words with values that are multiple of 137: {}".format(count))