纸牌游戏 Python
我这里有一段代码,用来把一张牌从牌堆移动到基础堆。我已经导入了必要的细节等等。我的问题是,这段代码太长了。有办法让它变得更短吗?怎么做呢?谢谢 :)
def dtof():
suit = raw_input("enter suit: ")
v = trash.pop()
if suit == "D":
if card.suitNumber[v.suit] == 1:
if card.rankNumber[v.rank] == 0:
Diamond.append(v)
elif card.rankNumber[v.rank] == card.rankNumber[Diamond[-1].rank] + 1:
Diamond.append(v)
else:
trash.append(v)
return Diamond[-1]
else:
trash.append(v)
elif suit == "H":
if card.suitNumber[v.suit] == 2:
if card.rankNumber[v.rank] == 0:
Heart.append(v)
elif card.rankNumber[v.rank] == card.rankNumber[Heart[-1].rank] + 1:
Heart.append(v)
else:
trash.append(v)
return Heart[-1]
else:
trash.append(v)
elif suit == "C":
if card.suitNumber[v.suit] == 4:
if card.rankNumber[v.rank] == 0:
Clubs.append(v)
elif card.rankNumber[v.rank] == card.rankNumber[Clubs[-1].rank] + 1:
Clubs.append(v)
else:
trash.append(v)
return Clubs[-1]
else:
trash.append(v)
elif suit == "S":
if card.suitNumber[v.suit] == 3:
if card.rankNumber[v.rank] == 0:
Spade.append(v)
elif card.rankNumber[v.rank] == card.rankNumber[Spade[-1].rank] + 1:
Spade.append(v)
else:
trash.append(v)
return Spade[-1]
else:
trash.append(v)
else:
trash.append(v)
1 个回答
0
想象一下,把方块、红心、梅花和黑桃这四种花色合并成一个字典,字典的键就是花色的名称。