将方法参数传递给父类构造函数（Flask -- ModelView.as_view()）

Question

这个问题更像是关于Python的一般性问题，而不是Flask的特定问题。

这段代码来自于 https://github.com/mitsuhiko/flask/blob/master/flask/views.py#L18。

@classmethod
def as_view(cls, name, *class_args, **class_kwargs):
    """Converts the class into an actual view function that can be used
    with the routing system.  Internally this generates a function on the
    fly which will instantiate the :class:`View` on each request and call
    the :meth:`dispatch_request` method on it.

    The arguments passed to :meth:`as_view` are forwarded to the
    constructor of the class.
    """
    def view(*args, **kwargs):
        self = view.view_class(*class_args, **class_kwargs)
        return self.dispatch_request(*args, **kwargs)

    if cls.decorators:
        view.__name__ = name
        view.__module__ = cls.__module__
        for decorator in cls.decorators:
            view = decorator(view)

    # we attach the view class to the view function for two reasons:
    # first of all it allows us to easily figure out what class-based
    # view this thing came from, secondly it's also used for instantiating
    # the view class so you can actually replace it with something else
    # for testing purposes and debugging.
    view.view_class = cls
    view.__name__ = name
    view.__doc__ = cls.__doc__
    view.__module__ = cls.__module__
    view.methods = cls.methods
    return view

有没有人能给我解释一下这个 as_view() 函数是怎么把它的参数传递给 View 类的构造函数的，就像方法注释里说的那样？

如果不能直接解释，能不能给我一些建议，告诉我具体需要学习Python的哪些内容，以便更好地理解发生了什么。

谢谢

Answer 1

这一行是关键：

self = view.view_class(*class_args, **class_kwargs)

它是把传递给 as_view 的参数拿来，用这些参数创建一个 view 的实例。