Python 2.7.1:如何打开、编辑和保存CSV文件
我在打开一个文件(amount2.csv)时遇到了问题,想修改一下,保存后再关闭这个文件。
请问怎么才能打开一个文件,编辑它,保存,然后关闭呢?
import csv
changes = {
'1 dozen' : '12'
}
with open('amount2.csv', 'r') as f:
reader = csv.reader(f)
print f
f.close()
我遇到的错误是:打开文件 'amount2.csv',模式 'r' 在 0x1004656f0(<> 已去掉)
2 个回答
0
你现在想打印文件对象本身,但这样做没什么实际用处。你有没有查看过CSV模块的文档?里面的第一个代码示例就教你怎么使用csv.reader。
23
你看到的内容其实不是错误,而是你使用的'print f'的结果。如果你想查看文件的内容,可以这样做:
<open file 'amount2.csv', mode 'r' at 0x1004656f0>
如果你想往文件里添加行,可以这样做:
with open('test.csv', 'rb') as f:
reader = csv.reader(f)
for row in reader:
# row is a list of strings
# use string.join to put them together
print ', '.join(row)
想了解更多信息,可以查看 Python CSV 文档
编辑:
我一开始理解错了,你是想把csv文件中所有的'1打'换成'12'。我先说,这个操作其实不使用csv模块会更简单,不过这里我给你一个使用它的解决方案。
changes = [
['1 dozen','12'],
['1 banana','13'],
['1 dollar','elephant','heffalump'],
]
with open('test.csv', 'ab') as f:
writer = csv.writer(f)
writer.writerows(changes)
如果你是编程新手,尤其是刚接触Python,这行代码可能会让你觉得比较棘手:
import csv
new_rows = [] # a holder for our modified rows when we make them
changes = { # a dictionary of changes to make, find 'key' substitue with 'value'
'1 dozen' : '12', # I assume both 'key' and 'value' are strings
}
with open('test.csv', 'rb') as f:
reader = csv.reader(f) # pass the file to our csv reader
for row in reader: # iterate over the rows in the file
new_row = row # at first, just copy the row
for key, value in changes.items(): # iterate over 'changes' dictionary
new_row = [ x.replace(key, value) for x in new_row ] # make the substitutions
new_rows.append(new_row) # add the modified rows
with open('test.csv', 'wb') as f:
# Overwrite the old file with the modified rows
writer = csv.writer(f)
writer.writerows(new_rows)
但这其实只是一个列表推导式,实际上等同于:
new_row = [ x.replace(key, value) for x in new_row ]
temp = []
for x in new_row:
temp.append( x.replace(key, value) )
new_row = temp