如何在PyObjC选择器中表示空指针?

3 投票
2 回答
1075 浏览
提问于 2025-04-15 11:30

我想在我设计的应用程序中使用一个NSOpenPanel(打开面板)。这是我目前的代码:

@objc.IBAction
def ShowOpenPanel_(self, sender):
    self.panel = NSOpenPanel.openPanel()
    self.panel.setCanChooseFiles_(False)
    self.panel.setCanChooseDirectories_(True)
    NSLog(u'Starting OpenPanel')
    self.panel.beginForDirectory_file_types_modelessDelegate_didEndSelector_contextInfo_(
        self.defaults.objectForKey_(u'projpath'), 
        objc.nil, 
        objc.nil, 
        self, 
        objc.selector(self.OpenPanelDidEnd_returnCode_contextInfo_, 
            signature='v:@ii'),
        objc.nil)
    NSLog(u'OpenPanel was started.')

def OpenPanelDidEnd_returnCode_contextInfo_(self, panel, returnCode, context):
    NSLog('Panel ended.')
    if (returnCode == NSOKButton):
        NSLog(u'User selected OK')
        path = self.panel.filenames()[0]
        self.defaults.setObject_forKey_(path, u'projpath')
    del self.panel

我最关心的主要有两行:

        objc.selector(self.OpenPanelDidEnd_returnCode_contextInfo_, 
            signature='v:@ii'),
        objc.nil) #this is the argument that gets passed as the void pointer

第三个参数应该是一个空指针。因为我不打算使用那个数据,所以我想把它留空。我尝试过把签名写成 'v:@iv',还试过用 objc.NULL 和 Python 的 None,以及这些东西的各种组合。请问处理这个问题的最佳方法是什么?

2 个回答

1

我觉得你根本不需要用到 objc.selector; 不如试试这个:

@objc.IBAction
def ShowOpenPanel_(self, sender):
    self.panel = NSOpenPanel.openPanel()
    self.panel.setCanChooseFiles_(False)
    self.panel.setCanChooseDirectories_(True)
    NSLog(u'Starting OpenPanel')
    self.panel.beginForDirectory_file_types_modelessDelegate_didEndSelector_contextInfo_(
        self.defaults.objectForKey_(u'projpath'), 
        objc.nil, 
        objc.nil, 
        self, 
        self.OpenPanelDidEnd_returnCode_contextInfo_,
        objc.nil)
    NSLog(u'OpenPanel was started.')

我还发现需要用 PyObjCTools.AppHelper.endSheetMethod 来装饰面板结束的函数:

@PyObjCTools.AppHelper.endSheetMethod
def OpenPanelDidEnd_returnCode_contextInfo_(self, panel, returnCode, context):
    NSLog('Panel ended.')
    if (returnCode == NSOKButton):
        NSLog(u'User selected OK')
        path = self.panel.filenames()[0]
        self.defaults.setObject_forKey_(path, u'projpath')
    del self.panel

这是我会写的你所拥有的代码:

@objc.IBAction
def showOpenPanel_(self, sender):
    panel = NSOpenPanel.openPanel()
    panel.setCanChooseFiles_(False)
    panel.setCanChooseDirectories_(True)
    NSLog(u'Starting openPanel')
    panel.beginForDirectory_file_types_modelessDelegate_didEndSelector_contextInfo_(
        self.defaults.objectForKey_(u'projpath'),    #forDirectory
        None,    #file
        None,    #types
        self,    #modelessDelegate
        self.openPanelDidEnd_returnCode_contextInfo_,    #didEndSelector
        None)    #contextInfo
    NSLog(u'openPanel started')

@PyObjCTools.AppHelper.endSheetMethod
def openPanelDidEnd_returnCode_contextInfo_(self, panel, returnCode, context):
    NSLog(u'Panel ended')
    if returnCode != NSOKButton:
        return
    NSLog(u'User selected OK')
    path = panel.filenames()[0]
    self.defaults.setObject_forKey_(path, u'projpath')

关于修改的解释:我总是使用 None 而不是 objc.nil,这样用到现在也没出过问题;我觉得你的面板不需要是 self 的一个属性,因为你在返回函数中已经获取到了它;在objc的约定中,函数的第一个字母通常是小写的。

1

打开面板的正确方法是:

@objc.IBAction
def showOpenPanel_(self, sender):
    panel = NSOpenPanel.openPanel()
    panel.setCanChooseFiles_(False)
    panel.setCanChooseDirectories_(True)
    NSLog(u'Starting openPanel')
    panel.beginForDirectory_file_types_modelessDelegate_didEndSelector_contextInfo_(
        self.defaults.objectForKey_(u'projpath'),    #forDirectory
        None,    #file
        None,    #types
        self,    #modelessDelegate
        'openPanelDidEnd:returnCode:contextInfo:',    #didEndSelector
        None)    #contextInfo
    NSLog(u'openPanel started')

Dan的代码也能正常工作,但在我看来,我的写法稍微清晰一点:你传递的不是实际的方法,而是应该被调用的方法的名字。

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