我该如何反序列化这个JSON对象？

Question

import simplejson
from urllib2 import urlopen
from simplejson import loads
from django.core import serializers
content = loads(urlopen('https://graph.facebook.com/1234676502/feed').read())
content =  simplejson.dumps(content,sort_keys=True, indent=4)
print content
json_serializer = serializers.get_serializer("json")()
json_serializer.deserialize(content)

在运行上面的Python代码时，我遇到了以下错误：

Traceback (most recent call last):
  File "/var/www/youedo/test.py", line 22, in <module>
    json_serializer = serializers.get_serializer("json")()
  File "/usr/local/lib/python2.6/dist-packages/django/core/serializers/__init__.py", line 63, in get_serializer
    _load_serializers()
  File "/usr/local/lib/python2.6/dist-packages/django/core/serializers/__init__.py", line 109, in _load_serializers
    register_serializer(format, BUILTIN_SERIALIZERS[format], serializers)
  File "/usr/local/lib/python2.6/dist-packages/django/core/serializers/__init__.py", line 51, in register_serializer
    module = importlib.import_module(serializer_module)
  File "/usr/local/lib/python2.6/dist-packages/django/utils/importlib.py", line 35, in import_module
    __import__(name)
  File "/usr/local/lib/python2.6/dist-packages/django/core/serializers/xml_serializer.py", line 6, in <module>
    from django.core.serializers import base
  File "/usr/local/lib/python2.6/dist-packages/django/core/serializers/base.py", line 7, in <module>
    from django.db import models
  File "/usr/local/lib/python2.6/dist-packages/django/db/__init__.py", line 14, in <module>
    if not settings.DATABASES:
  File "/usr/local/lib/python2.6/dist-packages/django/utils/functional.py", line 276, in __getattr__
    self._setup()
  File "/usr/local/lib/python2.6/dist-packages/django/conf/__init__.py", line 38, in _setup
    raise ImportError("Settings cannot be imported, because environment variable %s is undefined." % ENVIRONMENT_VARIABLE)
ImportError: Settings cannot be imported, because environment variable DJANGO_SETTINGS_MODULE is undefined.

...而当我打印内容时，它正确地打印出了JSON字符串。

编辑：2 import simplejson from urllib2 import urlopen from simplejson import loads from django.core import serializers content = loads(urlopen('https://graph.facebook.com/1234676502/feed').read())

json_serializer = serializers.get_serializer("json")()
json_serializer.get_deserialize(content)

我把这段代码放在我的view.py里，然后我得到了以下错误：

AttributeError at /rss

'Serializer' object has no attribute 'get_deserialize'

Request Method:     GET
Request URL:    http://127.0.0.1:8000/rss
Django Version:     1.2.4
Exception Type:     AttributeError
Exception Value:    

'Serializer' object has no attribute 'get_deserialize'

Answer 1

你的错误和json没有直接关系，错误信息明确指出它无法导入DJANGO_SETTINGS，这意味着你的django应用上下文没有设置好。解决这个问题最简单的方法是安装django扩展包，这个扩展包提供了一个命令./manage.py runscript，可以在你的django应用上下文中运行你的脚本。

你可以在这里找到Django扩展包

编辑：看了你的第二次编辑，我发现你使用了一个方法get_deserialize()，正确的方法应该是deserialize()，据我所知。