在线程中使用django的call_command出现问题
我想在一个线程里执行Django的call_method。以下是示例代码:
import sys
sys.path.append("/my/django/project/path/")
import threading
import time
# Import my django project configuration settings
from django.core.management import setup_environ
from mydjangoprojectname import settings
setup_environ(settings)
from django.core.management import call_command
class ServerStarter(threading.Thread):
def __init__(self):
super(ServerStarter, self).__init__()
print "ServerStarter instance created"
def run(self):
print "Starting Django Server..."
call_command("runserver", noreload=True)
if __name__ == '__main__':
starter = ServerStarter()
starter.start()
------------------------------
OutPut:
ServerStarter instance created
Starting Django Server...
ServerStarter instance created
Starting Django Server...
Validating models...
0 errors found
Django version 1.2.3, using settings 'mydjangoprojectname.settings'
Development server is running at http://127.0.0.1:8000/
Quit the server with CONTROL-C.
Django服务器正常启动,但ServerStarter被创建了两次。
而且这两个ServerStarter的实例都在运行。
如果我在run方法里注释掉call_command("runserver", noreload=True),那么只会
创建一个线程(这正是我想要的)。
提前谢谢你们!
2 个回答
5
我找到了解决办法(Chris Morgan说得对)。这段代码按我想要的方式运行:
import sys
sys.path.append("/my/django/project/path/")
import threading
# Import my django project configuration settings
from django.core.management import setup_environ, ManagementUtility
from mydjangoprojectname import settings
setup_environ(settings)
class ServerStarter(threading.Thread):
def __init__(self):
super(ServerStarter, self).__init__()
print "ServerStarter instance created"
def run(self):
print "Starting Django Server..."
utility = ManagementUtility()
command = utility.fetch_command('runserver')
command.execute(use_reloader=False)
if __name__ == '__main__':
starter = ServerStarter()
starter.start()
0
我觉得这可能是因为Django内部服务器在重新加载所有模块,这是它的常规操作。你可以试试类似于--noreload
的选项,用在call_command
上(可能是call_command("runserver", noreload=True)
,但我不太确定)。
(另外,QThread
是通过QApplication.exec_()
来启动的;除非你有特别的需求要提前启动,否则我认为你不需要自己去运行starter.start()
。)