Python argparse:根据前一个参数选择nargs +或*
我正在写一个服务器查询工具,最开始有一小段代码用来解析参数:
# Parse arguments
p = argparse.ArgumentParser()
g = p.add_mutually_exclusive_group(required=True)
g.add_argument('--odam', dest='query_type', action='store_const',
const='odam', help="Odamex Master query.")
g.add_argument('--odas', dest='query_type', action='store_const',
const='odas', help="Odamex Server query.")
p.add_argument('address', nargs='*')
args = p.parse_args()
# Default master server arguments.
if args.query_type == 'odam' and not args.address:
args.address = [
'master1.odamex.net:15000',
'master2.odamex.net:15000',
]
# If we don't have any addresses by now, we can't go on.
if not args.address:
print "If you are making a server query, you must pass an address."
sys.exit(1)
有没有更好的方法来做这个,最好能全部在解析器里面完成?最后那个错误看起来有点不太对劲,如果我能让地址的nargs根据是否传入--odam或---odas来决定就好了。我可以创建一个子解析器,但那样的话帮助信息看起来会有点奇怪,因为它会省略命令中的地址部分。
1 个回答
12
你可以通过自定义一个 argparse.Action 来实现这个功能:
import argparse
import sys
class AddressAction(argparse.Action):
def __call__(self, parser, args, values, option = None):
args.address=values
if args.query_type=='odam' and not args.address:
args.address=[
'master1.odamex.net:15000',
'master2.odamex.net:15000',
]
if not args.address:
parser.error("If you are making a server query, you must pass an address.")
p = argparse.ArgumentParser()
g = p.add_mutually_exclusive_group(required=True)
g.add_argument('--odam', dest='query_type', action='store_const',
const='odam', help="Odamex Master query.")
g.add_argument('--odas', dest='query_type', action='store_const',
const='odas', help="Odamex Server query.")
p.add_argument('address', nargs='*', action=AddressAction)
args = p.parse_args()
这样就能得到
% test.py --odas
If you are making a server query, you must pass an address.
% test.py --odam
Namespace(address=['master1.odamex.net:15000', 'master2.odamex.net:15000'], query_type='odam')
% test.py --odam 1 2 3
Namespace(address=['1', '2', '3'], query_type='odam')