如何使gtkDialog的默认响应也能在空格键触发时生效

Question

我设置了一个消息对话框，它的默认响应是gtk.RESPONSE_OK，也就是说，当用户按下回车键时，即使“确定”按钮没有被选中，程序也会自动点击“确定”按钮。我想让空格键也能触发这个默认响应。请问有什么好的方法吗？

我是在Linux环境下使用Python 2.4的。不幸的是，我没有权限升级Python版本。

Answer 1

我对pygtk完全是个新手，但我发现如果不对空格和回车做出反应，并且加上一个dialog.destroy()的调用，我就无法让@ptomato的例子和“你好，世界”的基础代码正常工作。就当我说的这些是我的经验吧。

#!/usr/bin/env python

# example helloworld.py

import pygtk
pygtk.require('2.0')
import gtk

def md_event(dialog, event):
    if event.keyval in (gtk.keysyms.Return, gtk.keysyms.space):
        dialog.response(gtk.RESPONSE_OK)
        dialog.destroy()
        return True
    elif event.keyval == gtk.keysyms.Escape:
        dialog.response(gtk.RESPONSE_CANCEL)
        dialog.destroy()
        return True
    return False

class HelloWorld:
    # This is a callback function. The data arguments are ignored
    # in this example. More on callbacks below.
    def hello(self, widget, data=None):
        print "Hello World"

    # Another callback
    def destroy(self, widget, data=None):
        gtk.main_quit()

    def create_message_dialog(self, x, y):
        md = gtk.MessageDialog(buttons=gtk.BUTTONS_OK_CANCEL, message_format="wawawawaaaaa")
        md.add_events(gtk.gdk.KEY_PRESS_MASK)
        md.connect("key-press-event", md_event)
        result = md.run()
        print result

    def __init__(self):
        # create a new window
        self.window = gtk.Window(gtk.WINDOW_TOPLEVEL)

        # Here we connect the "destroy" event to a signal handler.
        # This event occurs when we call gtk_widget_destroy() on the window,
        # or if we return FALSE in the "delete_event" callback.
        self.window.connect("destroy", self.destroy)

        # Sets the border width of the window.
        self.window.set_border_width(10)

        self.button2 = gtk.Button("Message Dialog")
        self.button2.connect("clicked", self.create_message_dialog, None)
        self.window.add(self.button2)
        self.button2.show()

        # and the window
        self.window.show()

    def main(self):
        # All PyGTK applications must have a gtk.main(). Control ends here
        # and waits for an event to occur (like a key press or mouse event).
        gtk.main()

def run_hello():
    hello = HelloWorld()
    hello.main()

# If the program is run directly or passed as an argument to the python
# interpreter then create a HelloWorld instance and show it
if __name__ == "__main__":
    run_hello()

Answer 2

在消息对话框上连接到 key-press-event 信号：

def on_dialog_key_press(dialog, event):
    if event.string == ' ':
        dialog.response(gtk.RESPONSE_OK)
        return True
    return False

dialog = gtk.MessageDialog(message_format='Some message', buttons=gtk.BUTTONS_OK_CANCEL)
dialog.add_events(gtk.gdk.KEY_PRESS_MASK)
dialog.connect('key-press-event', on_dialog_key_press)
dialog.run()

不过要记住，改变用户对界面的期望通常被认为是不太好的做法。