将视频上传到Google App Engine Blobstore

3 投票
3 回答
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提问于 2025-04-16 02:19

我想把一个视频文件和一些属性关联起来,但我发现用户无法在一个表单里完成所有操作——给视频命名、提供描述、回答一些问题,还要上传文件。

我希望能按照以下步骤进行:

  1. 用户打开一个页面,里面有一个表单,表单里有这些字段:名称、描述、文件选择器。
  2. 文件会被存储为一个二进制大对象(blob),同时记录下名称和描述的ID。

有没有人能分享一些相关的例子或者教程让我学习?我在谷歌上找到的教程只显示了上传文件后重定向到文件的内容。

谢谢,抱歉问了个新手问题!

3 个回答

1

这是我完成这个任务的方法。其实比你想的要简单得多。请注意以下内容,摘自Blobstore 概述“当 Blobstore 处理用户的请求时,上传文件的 MIME 部分会被清空,blob 键会作为 MIME 部分的头信息添加。所有其他表单字段和部分都会被保留,并传递给上传处理程序。” 在上传处理程序中,你可以对其他表单字段进行任何你想做的操作。

    class Topic(db.Model):
        title = db.StringProperty(multiline=False)
        blob = blobstore.BlobReferenceProperty()
        imageurl = db.LinkProperty()

    class MainHandler(webapp.RequestHandler):
        def get(self):
            upload_url = blobstore.create_upload_url('/upload')
            self.response.out.write('<html><body>')
            self.response.out.write('<form action="%s" method="POST" enctype="multipart/form-data">' % upload_url)
            self.response.out.write("""Upload File: <input type="file" name="file"><br>
            <div><label>Title:</label></div>
            <div><textarea name="title" rows="1" cols="25"></textarea></div><input type="submit" 
                name="submit" value="Submit"> </form>""")
            self.response.out.write('<br><br><h2>TOPIC LIST</h2><table border="1"><tr><td>')
            for topic in Topic.all():                
                self.response.out.write('<div><img src="%s=s48"/>' % topic.imageurl)
                self.response.out.write('<div><b>Image URL: </b><i>%s</i></div>' % topic.imageurl)
                self.response.out.write('<div><b>Title: </b><i>%s</i></div>' % topic.title)
            self.response.out.write('</td></tr></table><br>') 
            self.response.out.write('</body></html>')

    class UploadHandler(blobstore_handlers.BlobstoreUploadHandler):
        def post(self):
            upload_files = self.get_uploads('file')  # 'file' is file upload field in the form
            blob_info = upload_files[0]
            topic = Topic()
            topic.title = self.request.get("title")
            topic.blob = blob_info.key()
            topic.imageurl = images.get_serving_url(str(blob_info.key()))
            topic.put()        
            self.redirect('/')
def main():
    application = webapp.WSGIApplication(
          [('/', MainHandler),
           ('/upload', UploadHandler),
          ], debug=True)
    run_wsgi_app(application)
3

这是我用来上传图片并把它们和文章关联起来的代码。最难的部分是如何把文章的ID传到上传处理程序。我通过把文件名设置为文章的ID来解决这个问题。

from lib import urllib2_file
from lib.urllib2_file import UploadFile

# this view serves a task in a queue
def article(request):
       article = Article.objects.get(id=form.cleaned_data['article'])

       try:
            image = StringIO(urllib2.urlopen(image_url).read())
        except (urllib2.HTTPError, DownloadError):
            article.parsed = True
            article.save()
        else:
            image = UploadFile(image, '.'.join([str(article.id), image_url.rsplit('.', 1)[1][:4]]))
            upload_url = blobstore.create_upload_url(reverse('Articles.views.upload'))

            try:
                urllib2.urlopen(upload_url, {'file': image})
            except (DownloadError, RequestTooLargeError):
                pass

    return HttpResponse(json.dumps({'status': 'OK'}))

def upload(request):
    if request.method == 'POST':
        blobs = get_uploads(request, field_name='file', populate_post=True)

        article = Article.objects.get(id=int(blobs[0].filename.split('.')[0]))
        article.media = blobs[0].filename
        article.parsed = True
        article.save()

        return HttpResponseRedirect(reverse('Articles.views.upload'))
    else:
        return HttpResponse('meow')

    def upload(request):
        if request.method == 'POST':
            blobs = get_uploads(request, field_name='file', populate_post=True)

            article = Article.objects.get(id=int(blobs[0].filename.split('.')[0]))
            article.media = blobs[0].filename
            article.parsed = True
            article.save()

            return HttpResponseRedirect(reverse('Articles.views.upload'))
        else:
            return HttpResponse('meow')

# this serves the image
def image(request):
    blob = BlobInfo.gql("WHERE filename='%s' LIMIT 1" % request.form.cleaned_data['id'])[0]

    return HttpResponse(BlobReader(blob.key()).read(),
                        content_type=blob.content_type)

另外,你还需要这个链接:http://fabien.seisen.org/python/urllib2_file/

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