在ThreadPoolExecutor中,socket.bind() 阻塞但没有“地址已在使用”错误
我正在写一个使用socket的Python程序,并测试在同一个端口上监听两次,使用的是ThreadPoolExecutor。下面是一个简单的程序,能重现我遇到的问题:
import socket
import time
import concurrent.futures
def listen6666():
server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server_socket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
print("set socket")
server_socket.bind(("localhost", 6666))
server_socket.listen()
print("done")
server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server_socket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
server_socket.bind(("localhost", 6666))
server_socket.listen()
with concurrent.futures.ThreadPoolExecutor(max_workers=5) as executor:
fn = executor.submit(listen6666)
fn2 = executor.submit(listen6666)
# listen6666() - "Address already in use"
#fn.result() - "Address already in use"
#fn2.result() - "Address already in use"
time.sleep(10)
我本来期待在server_socket.bind
的listen6666
中会出现“地址已在使用中”的错误,但它就是没有反应。所以完整的输出是:
$ python test.py
set socket
set socket
$
如果我在没有executor的情况下调用listen6666(),或者在睡眠之前调用fn.result(),那么“地址已在使用中”的错误确实会出现。我希望在listen6666()中也能出现“地址已在使用中”的错误。
我该怎么解决这个问题呢?
1 个回答
0
你需要在这个线程中处理异常情况。
下面是你代码的一个修改版本,展示了一个“地址已经在使用中”的异常是如何被抛出的。
import socket
import concurrent.futures
ADDRESS = "localhost", 6666
def listen6666(keep=False):
server_socket = None
try:
server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server_socket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
print("bind")
server_socket.bind(ADDRESS)
print("listen")
server_socket.listen()
print("done")
except Exception as e:
print(e)
finally:
if keep:
return server_socket
if server_socket is not None:
server_socket.close()
server_socket = None
try:
server_socket = listen6666(True)
with concurrent.futures.ThreadPoolExecutor(max_workers=5) as executor:
executor.submit(listen6666)
executor.submit(listen6666)
except Exception as e:
print(e)
finally:
if server_socket is not None:
server_socket.close()
输出结果:
bind
listen
done
bind
bind
[Errno 48] Address already in use
[Errno 48] Address already in use