使用Paramiko在SFTP中执行'put'操作

Question

我安装了Paramiko这个库，并写了以下代码，但它无法上传文件。它可以轻松地下载文件，并且可以在上面执行ls命令。

#set username & password
username='runaway'
password='runaway'
port=22
source= '/Unzip.sh' 
destination ='/var/mpx/www/http'


#SFTP
client.load_system_host_keys()
print " hostname =%s \n username=%s \n password=%s \n" (hostname,username,password)
t = paramiko.Transport((hostname, port)) 
t.connect(username=username,password=password)
sftp = paramiko.SFTPClient.from_transport(t)
sftp.put(source,destination)
#sftp.close()
#t.close()

使用'put'命令时出现了以下错误和堆栈跟踪 -

File "upload_file.py", line 84, in ?
    sftp.put(source,destination)
  File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 522, in put
    fr = self.file(remotepath, 'wb')
  File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 221, in open
    t, msg = self._request(CMD_OPEN, filename, imode, attrblock)
  File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 572, in _request
    return self._read_response(num)
  File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 619, in _read_response
    self._convert_status(msg)
  File "/usr/lib/python2.4/site-packages/paramiko/sftp_client.py", line 649, in _convert_status
    raise IOError(text)
IOError: Failure

我该如何解决这个问题呢？

Answer 1

在2.0.2版本中，当你尝试使用 sftp.mkdir('/exists') 创建一个文件夹时，也会出现这个问题：

Traceback (most recent call last):
  ...
  File "/usr/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 380, in mkdir
    self._request(CMD_MKDIR, path, attr)
  File "/usr/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 730, in _request
    return self._read_response(num)
  File "/usr/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 781, in _read_response
    self._convert_status(msg)
  File "/usr/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 811, in _convert_status
    raise IOError(text)
IOError: Failure

这是我在Python 2.7.9中解决这个问题的方法：

try:
    sftp.mkdir(remote_dir)
except IOError:
    logging.debug('%s already exists.', remote_dir)

Answer 2

这个解决办法让我觉得挺有意思的！

source= '/Unzip.sh' 
destination ='/var/mpx/www/http/Unzip.sh'

我只是把目标路径改了一下，把文件名也加上了。没想到会从一个Python包里出现这样的错误。