遍历列表以添加值

Question

我正在尝试在Python中把一个txt文件的内容添加到一个列表里，然后遍历这个列表，找出所有的数字并把它们加在一起。

示例文本：

Alabama 4780
Alaska 710
Arizona 6392
Arkansas 2916
California 37254
Colorado 5029

预期输出：

['Alabama', '4780', 'Alaska', '710', 'Arizona', '6392', 'Arkansas', '2916', 'California', '37254', 'Colorado', '5029']

total population: 57621

我可以把数字添加到列表里，但就是无法计算出所有数字的总和。理想情况下，我希望能把这些操作都放在一个函数里。

def totalpoplst(filename):
    lst = []
    with open(filename) as f:
        for line in f:
            lst += line.strip().split(' ')
        return print(lst)
    totalpop()

def totalpop(filename):
    total_pop = 0
    for i in lst:
        if  i.isdigit():
            total_pop = total_pop + i.isdigit()
    return print(total_pop)

def main():
    filename = input("Please enter the file's name: ")
    totalpoplst(filename)

main()

Answer 1

f = open('your_file.txt')  
your_dict={}
total_pop = 0
for x in f:
    x=x.strip()
    s,p=x.split(' ')
    your_dict[s]=p
    total_pop +=int(p)
print your_dict
print total_pop

使用字典会更好

Answer 2

你需要把提供的人口数据从字符串形式转换成数字。要做到这一点，把这一行代码改成：

total_pop = total_pop + i.isdigit()

改成：

total_pop = total_pop + int(i)

Answer 3

用 dict 来存储键值对的数据比用列表要好。

>>> population = {}
>>> total = 0
>>> with open('list.txt', 'r') as handle:
...     for line in handle:
...         state, sep, pop = line.partition(' ')
...         population[state] = int(pop)
...         total += population[state]
... 
>>> total
57081