为什么方法调用后的命名空间会变化?
我正在创建一个类,但在Python中处理命名空间时遇到了一些麻烦。
你可以看到下面的代码,它大部分都能正常工作,但在调用guiFrame._stateMachine()
之后,时间模块似乎就不再被定义了。
如果我在_stateMachine()
里重新导入时间模块,它就能正常工作。但是,为什么在头部导入时间模块后,它在命名空间里却不见了呢?
我是不是漏掉了什么?
错误信息:
File "C:\Scripts\Python\GUI.py", line 106, in <module>
guiFrame._stateMachine()
File "C:\Scripts\Python\GUI.py", line 74, in _stateMachine
self.tempfile.write('%s cpuUMTS %s\n' % (time.asctime(time.localt
f.load.cpuThreadsValue['10094']))
UnboundLocalError: local variable 'time' referenced before assignment
代码:
import os
import cpu_load_internal
import throughput_internal
import matplotlib
matplotlib.use('Agg')
import matplotlib.pyplot as plt
from Tkinter import *
import tkMessageBox
import time
class GUIFramework(Frame):
"""This is the GUI"""
def __init__(self,master=None):
"""Initialize yourself"""
"""Initialise the base class"""
Frame.__init__(self,master)
"""Set the Window Title"""
self.master.title("Type Some Text")
"""Display the main window
with a little bit of padding"""
self.grid(padx=10,pady=10)
self.CreateWidgets()
plt.figure(1)
def _setup_parsing(self):
self.load = cpu_load_internal.CPULoad('C:\Templogs')
self.throughput = throughput_internal.MACThroughput('C:\Templogs')
self.tempfile = open('output.txt','w')
self.state = 0
def _parsing(self):
self.load.read_lines()
self.throughput.read_lines()
self.cpuLoad.set(self.load.cpuThreadsValue['10094'])
self.macThroughput.set(self.throughput.macULThroughput)
def __change_state1(self):
self.state = 2
def __change_state3(self):
self.state = 3
def CreateWidgets(self):
"""Create all the widgets that we need"""
"""Create the Text"""
self.cpuLoad = StringVar()
self.lbText1 = Label(self, textvariable=self.cpuLoad)
self.lbText1.grid(row=0, column=0)
self.macThroughput = StringVar()
self.lbText2 = Label(self, textvariable=self.macThroughput)
self.lbText2.grid(row=0, column=1)
self.butStart = Button(self, text = 'Start', command = self.__change_state1)
self.butStart.grid(row=1, column=0)
self.butStop = Button(self, text = 'Stop', command = self.__change_state3)
self.butStop.grid(row=1, column=1)
def _stateMachine(self):
if (self.state == 2):
print self.throughput.macULUpdate
print self.load.cpuUpdate
if self.load.cpuUpdate:
self.load.cpuUpdate = 0
print 'cpuUMTS %s\n' % (self.load.cpuThreadsValue['10094'])
self.tempfile.write('%s cpuUMTS %s\n' % (time.asctime(time.localtime()), self.load.cpuThreadsValue['10094']))
if self.throughput.macULUpdate:
self.throughput.macULUpdate = 0
print 'macUL %s %s\n' % (self.throughput.macULThroughput, self.throughput.macULThroughputUnit)
self.tempfile.write('%s macUL %s %s\n' % (time.asctime(time.localtime()), self.throughput.macULThroughput, self.throughput.macULThroughputUnit))
if (self.state == 3):
self.tempfile.seek(0)
plt.plot([1,2,3],[1,4,6])
plt.savefig('test.png')
self.state == 0
while 1:
try:
line = (self.tempfile.next())
except:
break
if 'cpuUMTS' in line:
line.split
time = 4
if __name__ == "__main__":
guiFrame = GUIFramework()
print dir(guiFrame)
guiFrame._setup_parsing()
guiFrame.state = 2
while(1):
guiFrame._parsing()
guiFrame._stateMachine()
guiFrame.update()
time.sleep(0.1)
3 个回答
2
你在这个方法里试图给变量 time
赋值:
time = 4
所以编译器认为 time
一定是一个局部变量,但其实并不是。这就是为什么当你想使用 time
模块时会出现错误,即使你在给 time
赋值之前就尝试使用这个模块。
2
你似乎把时间当成了一个变量。这里发生了什么:
"C:\Scripts\Python\GUI.py" 文件的第74行
7
你为什么要给 time
赋值呢?这样做会让它变成一个局部变量,但这会遮盖掉模块里的 time
!如果你仔细看看,系统会提示你在给 time
赋值之前就使用了它——因为你想在 _stateMachine
里把它当作局部变量来用。
time = 4