帮助你计算矩阵。
xmatrix的Python项目详细描述
X矩阵
- 一个计算矩阵数学问题的python包。在
- python版本：3.6及以上。在
用法
安装
pip3 install xmatrix --upgrade
在文件中添加导入
^{pr2}$
创建矩阵
- 矩阵（“行；行…”）或矩阵（[[1,2,3]，[4,5,6]，[7,8,9]]）
- xm（“行；行…”）或xm（[[1,2,3]，[4,5,6]，[7,8,9]]）
my_matrix=Matrix("1,2;3,4")my_matrix_also_equal_to=xm("1,2;3,4")#result:[1,2][3,4]
我们还支持更大的矩阵
my_matrix=xm("1,2,3;4,5,6;7,8,9")#result:[1,2,3][4,5,6][7,8,9]
简单计算
my_matrix=xm("1,2;3,4")my_matrix2=xm("4,6;2,9")print(my_matrix+my_matrix2)#result:[5,8][5,13]print(my_matrix-my_matrix2)#result:[-3,-4][1,-5]print(my_matrix*my_matrix2)#result:[8,24][20,54]print(my_matrix*87)#result:[87,174][261,348]print(my_matrix**7)#result:[30853,44966][67449,98302]print(my_matrix==my_matrix2)#result:False
转置矩阵
my_matrix=xm("1,2,3;4,5,6;7,8,9")print(my_matrix)#result:[1,2,3][4,5,6][7,8,9]print(my_matrix.transpose)print(my_matrix.tp)#result:[1,4,7][2,5,8][3,6,9]my_matrix2=xm("1,2,3,4;5,6,7,8;9,10,11,12;13.1,14.2,15.3,16.4")print(my_matrix2)#result:[1,2,3,4][5,6,7,8][9,10,11,12][13.1,14.2,15.3,16.4]print(my_matrix2.tp)#result:[1,5,9,13.1][2,6,10,14.2][3,7,11,15.3][4,8,12,16.4]
逆
my_matrix=xm("1,2;3,4")print(my_matrix)#result:[1,2][3,4]print(my_matrix.inverse)print(my_matrix.iv)#result:[-2,1][1.5,-0.5]#special use by '**' power operator:print(my_matrix**-1)#result:[-2,1][1.5,-0.5]my_matrix2=xm("1,2,3;4,5,6;7,8,9")print(my_matrix2)#result:[1,2,3][4,5,6][7,8,9]print(my_matrix2.iv)#result:#The determinant is zero, can't be inverse.#Nonemy_matrix3=xm("1,1,1;1,2,3;1,4,5")print(my_matrix3)#result:[1,1,1][1,2,3][1,4,5]print(my_matrix3.inverse)#result:[1,0.5,-0.5][1,-2,1][-1,1.5,-0.5]my_matrix4=xm("1,1,2,1;1,1,0,0;1,1,0,1;1,0,1,0")print(my_matrix4)#result:[1,1,2,1][1,1,0,0][1,1,0,1][1,0,1,0]print(my_matrix4.iv)#result:[-0.5,0,0.5,1][0.5,1,-0.5,-1][0.5,0,-0.5,0][0,-1,1,0]#and more...
按列表获取矩阵
my_matrix=xm("1,2,3;4,5,6;7,8,9")print(my_matrix.raw)#result:[[1,2,3],[4,5,6],[7,8,9]]
获取单位矩阵
i=IdentityMatrix(3)i_also_equal_to=ixm(3)#result:print(i)[1,0,0][0,1,0][0,0,1]
高斯消去行缩减梯队形式
my_matrix=xm('1,-3,2,8;-1,4,-2,-9;-3,9,4,6')#resultprint(my_matrix)[1,-3,2,8][-1,4,-2,-9][-3,9,4,6]# Row Reduced Echelon Form (rref)print(my_matrix.rref)[1,0,0,-1][0,1,0,-1][0,0,1,3]
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