java异常、算术异常和对象

Question

当我运行下面的代码时，它给出了输出“算术异常”。由于算术异常是检查异常，因此它的优先级高于未检查异常。 但它如何区分对象异常和算术异常呢

public class Solution {


public static void a(Exception e)
{
    System.out.println("Exception");

}
public static void a(ArithmeticException ae)
{
    System.out.println("ArithmeticException");
}

public static void a(Object o)
{
    System.out.println("Object");
}

public static void main(String[] args)
{
    a(null);
}

}

Answer 1

重载方法时，将选择最具体的方法。在你的情况下，选择的顺序是

Arithmetic Exception > Exception > Object

根据^{}大多数特定方法在运行时选择

If more than one member method is both accessible and applicable to a method invocation, it is necessary to choose one to provide the descriptor for the run-time method dispatch. The Java programming language uses the rule that the most specific method is chosen.

Arithmetic Exception比Exception更具特异性，后者比Object更具特异性

Answer 2

在方法重载的情况下，Java语言将选择最具体的匹配，参数通过继承相互关联

我们将用一个例子来演示这种行为

    public static void main(String[] args) {
        a(new Exception("some exception"));
        a(new ArithmeticException("something went wrong with numbers."));
        a(new String("hello world"));
        a(null);
    }

产出如预期：