java选择并迭代具有相同名称的元素和子元素（Jsoup）

Question

我需要通过jsoup解析一个页面。该页面包含带有标签div、h3、a等的元素。我想分析这些元素并选择a（即标题）以在jList中显示

例如，该页面如下所示：

<div class="start">
    <div class="g">
        <div class="abc">
            <a class="picture" href="www.img.com"><img src="img" alt="image1"></a>
            <div class="xyz">
                <h3 class="_r">
                    <a class="title" href="www.example.com" onmousedown="return rwt(this,'','','','1','adf','','ahahh','','',event)">THIS IS <em>example</em>1</a>
                </h3>
            </div>
        </div>
    </div>

    <div class="g">
        <div class="abc">
            <a class="picture" href="www.img.com"><img src="img" alt="image2"></a>
            <div class="xyz">
                <h3 class="_r">
                    <a class="title" href="www.example.com" onmousedown="return rwt(this,'','','','1','adf','','ahahh','','',event)">lead by this<em>example</em></a>
                </h3>
            </div>
        </div>
    </div>

    <div class="g">
        <div class="abc">
            <a class="picture" href="www.img.com"><img src="img" alt="image3"></a>
            <div class="xyz">
                <h3 class="_r">
                    <a class="title" href="www.example.com" onmousedown="return rwt(this,'','','','1','adf','','ahahh','','',event)">showed<em>example</em>for the people</a>
                </h3>
            </div>
        </div>
    </div>

    <div class="g">
        <div class="abc">
            <a class="picture" href="www.img.com"><img src="img" alt="image4"></a>
            <div class="xyz">
                <h3 class="_r">
                    <a class="title" href="www.example.com" onmousedown="return rwt(this,'','','','1','adf','','ahahh','','',event)">we set<em>example</em>for people</a>
                </h3>
            </div>
        </div>
    </div>
</div>

代码如下：

String url = "http://www.google.com/search?q=example&tbm=nws&source=lnms";
String title = "";
try {
    Document doc = Jsoup.connect(url).userAgent("Chrome").timeout(5000).get();
    Elements e = doc.select("div.g");
    for (Element e1 : e) {
        title = e1.getElementsByTag("a").text();
    }
    DefaultListModel<String> listModel = new DefaultListModel<>();
    listModel.addElement(title);
    jList.setModel(listModel);
} catch (IOException ex) {
    Logger.getLogger(MainUI.class.getName()).log(Level.SEVERE, null, ex);
}

我得到的输出是最后一个元素div.g的标题：

we set example for people

我想从每个div.g中选择标题，并在jList中单独显示每个标题，如下所示：

THIS IS example 1
lead by this example
showed example for the people
we set example for people

Answer 1

当前，您将刮取的数据分配给循环中的title，然后将title分配给jlist的循环之外的。因此，循环完成后title的值始终是最后一个值

替换这个

for (Element e1 : e) {
    title = e1.getElementsByTag("a").text();
}
DefaultListModel<String> listModel = new DefaultListModel<>();
listModel.addElement(title);

用这个

DefaultListModel<String> listModel = new DefaultListModel<>();
for (Element e1 : e) {
    listModel.addElement(e1.getElementsByTag("a").text());
}

Answer 2

实际上，你不会每次都添加标题。循环用找到的新值替换每个时间标题，然后在循环后将其添加到列表中。像这样的事情可能会按照你想要的方式进行：

    DefaultListModel<String> listModel = new DefaultListModel<>();  
    for (Element e1 : e) {
       listModel.addElement(e1.getElementsByTag("a").text());
    }