JAVA尝试遍历字符串时出现lang.StringIndexOutOfBoundsException

3 日，18 小时 Questions & Answers 68

我正在尝试编写一个应用程序，它接受用户输入并将其转换为摩尔斯电码

功能代码：

    public static String[] stringToMorseSequence(String stringOfLetters){
        int lenStringOfLetters = stringOfLetters.length();
        String output[] = new String[1];

        String compInterpreted = "";
        for(int i = 0; i < lenStringOfLetters; i++) {
            String focus = String.valueOf(stringOfLetters.charAt(i));
            String nextCharacter = "";
            if (i != lenStringOfLetters) {
                nextCharacter = String.valueOf(stringOfLetters.charAt(i + 1));
            } else {
                nextCharacter = "END";
            }

            if (focus == " ") {
                compInterpreted = compInterpreted + "#";
            } else {
                String morseSequence = processCharacter(focus);
                if (morseSequence == "") {

                } else if (i == lenStringOfLetters) {
                    compInterpreted = compInterpreted + "!";
                } else if (nextCharacter != "END") {
                    if (nextCharacter != " "){
                        compInterpreted = compInterpreted + morseSequence + "@";
                    } else {
                        compInterpreted = compInterpreted + morseSequence;
                    }
                }
            }
        }
        Log.i("MORSE","Computer interpretable morse sequence = " + compInterpreted);
        output[0] = compInterpreted;

        String prettySequence = "";
        for(int i = 0; i-1 < output[0].length(); i++) {
            switch(String.valueOf(output[0].charAt(i))){
                case("#"):
                    prettySequence = prettySequence + "  ";
                case("@"):
                    prettySequence = prettySequence + " ";
                default:
                    prettySequence = prettySequence + output[0].charAt(i);
            }
        }
        Log.i("MORSE","Human interpretable morse sequence = " + prettySequence);
        output[1] = prettySequence;

        return output;
    }

我似乎收到了这个例外

E/AndroidRuntime: FATAL EXCEPTION: main
              Process: me.merhlim.jessica.morsecode, PID: 5687
              java.lang.StringIndexOutOfBoundsException: length=10; index=10
                  at java.lang.String.charAt(Native Method)
                  at me.merhlim.jessica.morsecode.MorseProcessing.stringToMorseSequence(MorseProcessing.java:16)
                  at me.merhlim.jessica.morsecode.texttomorse$7.onClick(texttomorse.java:112)
                  at 安卓.view.View.performClick(View.java:6294)
                  at 安卓.view.View$PerformClick.run(View.java:24770)
                  at 安卓.os.Handler.handleCallback(Handler.java:790)
                  at 安卓.os.Handler.dispatchMessage(Handler.java:99)
                  at 安卓.os.Looper.loop(Looper.java:164)
                  at 安卓.app.ActivityThread.main(ActivityThread.java:6494)
                  at java.lang.reflect.Method.invoke(Native Method)
                  at com.安卓.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:440)
                  at com.安卓.internal.os.ZygoteInit.main(ZygoteInit.java:807)
                  at de.robv.安卓.xposed.XposedBridge.main(XposedBridge.java:108)

我知道这是一个逻辑错误，但我不确定这个错误在哪里，或者如何解决它。正如错误消息所提到的，当试图解析字符串中的特定字符时，这是一个索引错误，但是我不确定我得到的不正确的逻辑是什么，导致了这个错误

我是java新手，而且时间很晚，所以我可能只是没有完全理解我正在编写的逻辑中的问题

如果这还不足以回答我的问题，我可以提供更多信息

感谢您花时间阅读此文章，如果您提供帮助，我们将不胜感激 -杰西卡

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JAVA尝试遍历字符串时出现lang.StringIndexOutOfBoundsException

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