Java：如何找到数组的最小值（用户输入）

Question

到目前为止，这是我的代码：

public static void main(String[] args) 
{
    System.out.println("Please input numbers");
    Scanner myScan = new Scanner(System.in);

    String input = myScan.nextLine();
    String[] numbers = input.split(" ");
    int[] numbersInt = new int[numbers.length];


    int minNumber = numbersInt[0];

    for(int i = 0 ; i < numbers.length; i++)
    {
        numbersInt[i] = Integer.parseInt(numbers[i]);
    }

    for(int i = 1; i < numbers.length; i++)
    {
        if(numbersInt[i] < minNumber)
        {
            minNumber = numbersInt[i];
        }else if(minNumber < numbersInt[i])
        {
            minNumber = numbersInt[0];
        }
        }

        System.out.println(minNumber);

    }
    }

例如，如果我输入整数'20 15 60'，我得到的数字“20”是最小值。我做错了什么？多谢各位

Answer 1

Solution 1

问题只针对两条线

1-移动int minNumber = numbersInt[0]（将其放在第一个for之后）

2-删除第二个for中下面的片段

  else if(minNumber < numbersInt[i])
        {

          minNumber = numbersInt[0];

        }

Finally, your code can be as follows

public static void main(String[] args) {

        System.out.println("Please input numbers");
        Scanner myScan = new Scanner(System.in);

        String input = myScan.nextLine();
        String[] numbers = input.split(" ");
        int[] numbersInt = new int[numbers.length];


        for (int i = 0; i < numbers.length; i++) {
            numbersInt[i] = Integer.parseInt(numbers[i]);
        }

        //Changed
        int minNumber = numbersInt[0];

        for (int i = 1; i < numbers.length; i++) {

            if (numbersInt[i] < minNumber) {
                minNumber = numbersInt[i];
            } 
            //Changed (deleted)
        }

        System.out.println(minNumber);

    }

Solution 2

我建议您在场景中使用此代码

  public static void main(String[] args) {

        System.out.println("Please enter numbers, if you wanna stop just enter non numeric input");
        Scanner scanner = new Scanner(System.in);

        //Get input numbers and add it to the list
        List<Integer> numberList = new ArrayList<Integer>();
        while (scanner.hasNextInt()) {
            numberList.add(scanner.nextInt());
        }

        //Get the minimum of numberList
        System.out.println("Min :" + Collections.min(numberList));

    }

Answer 2

你的代码是正确的，但有一些错误。首先，移动“int minNumber=numbersInt[0]；”第一个for循环之后的行。其次，从第二个for循环中删除else部分

为了让你更好地理解我再次发布你的代码：）并进行修复

public static void main(String[] args) {
        System.out.println("Please input numbers");
        Scanner myScan = new Scanner(System.in);

        String input = myScan.nextLine();
        String[] numbers = input.split(" ");
        int[] numbersInt = new int[numbers.length];


        for (int i = 0; i < numbers.length; i++) {
            numbersInt[i] = Integer.parseInt(numbers[i]);
        }

        int minNumber = numbersInt[0];

        for (int i = 1; i < numbers.length; i++) {
            if (numbersInt[i] < minNumber) {
                minNumber = numbersInt[i];
            }
        }

        System.out.println(minNumber);

    }

Answer 3

在解析整数之后，应该初始化minNumber。如果没有必要，也可以。所以这条线应该移动：

int minNumber = numbersInt[0];

所以你的代码是这样的：

System.out.println("Please input numbers");
Scanner myScan = new Scanner(System.in);

String input = myScan.nextLine();
String[] numbers = input.split(" ");
int[] numbersInt = new int[numbers.length];

for(int i = 0 ; i < numbers.length; i++)
{
    numbersInt[i] = Integer.parseInt(numbers[i]);
}
int minNumber = numbersInt[0];
for(int i = 1; i < numbers.length; i++)
{
    if(numbersInt[i] < minNumber)
    {
        minNumber = numbersInt[i];
    }
}
System.out.println(minNumber);

虽然这不是读取一行整数的真正方法。你可以这样做：

Scanner myScan = new Scanner(System.in);
System.out.println("How many numbers do you want to enter?");
int n = myScan.nextInt();

System.out.println("Please input numbers");

int[] numbersInt = new int[n];
for(int i = 0 ; i < n; i++)
{
    numbersInt[i] = myScan.nextInt();
}