java如何解析此消息！关于异常消息

Question

message=“”

Validation failed for classes [com.PointsSystem.entity.Membership] during persist time for groups [javax.validation.groups.Default, ]\nList of constraint violations:[\n\tConstraintViolationImpl{interpolatedMessage='请输入正确的手机号(11位)', propertyPath=cellPhone, rootBeanClass=class com.PointsSystem.entity.Membership, messageTemplate='请输入正确的手机号(11位)'}\n\tConstraintViolationImpl{interpolatedMessage='lastName 不能为空', propertyPath=lastName, rootBeanClass=class com.PointsSystem.entity.Membership, messageTemplate='lastName 不能为空'}\n]

“”

我不想在我的web应用程序上打印此消息，我需要获取包含中文字符的关键字“interpolatedMessage”。我该怎么做？此消息是在我使用e.getMessage时获取的，e.getMessage是一个异常

Answer 1

您必须捕获或编写ConstraintViolationException的处理程序

@ExceptionHandler(ConstraintViolationException.class)
    public ResponseEntity<ApiResponse> handleConstraintViolation(final ConstraintViolationException exception,
            final WebRequest request) {
        final List<String> errors = exception.getConstraintViolations()
                .parallelStream()
                .map(violation -> violation
                      .getInvalidValue() + " : " + violation.getMessage())
                .collect(Collectors.toList());
        return new ResponseEntity<>(errors, HttpStatus.BAD_REQUEST);

    }

或者在抓块里

try {
} catch() {
   final List<String> errors = exception.getConstraintViolations()
                    .parallelStream()
                    .map(violation -> violation
                          .getInvalidValue() + " : " + violation.getMessage())
                    .collect(Collectors.toList());
}