java停止当前线程,直到调用的线程完成,然后继续它
假设我有这两种方法,它们一直在互相调用:
public void run() {
try {
Thread.sleep(1000);
System.out.println("Thread " +
Thread.currentThread().getId() +
" is running");
posses(numberOfPlayers, players);
} catch (Exception e) {
System.out.println("Exception Caught");
}
}
synchronized public void posses(int n, Players[] players) throws InterruptedException {
Random rand = new Random();
Scanner input = new Scanner(System.in);
for (int i = 0; i < players.length; i++) {
if (players[i].haveBall)
System.out.println("Player" + i + ", ");
}
System.out.println(" \bhave the ball now");
for (int i = 1; i < numberOfPlayers; i++) {
if (players[i].haveBall) {
System.out.println("\nList of available players to pass for player " + i + ": ");
for (int j = 1; j < numberOfPlayers; j++) {
if (players[j].isActive && j != i) {
System.out.println("Player " + players[j].number);
}
}
System.out.println();
do {
receiver = rand.nextInt(numberOfPlayers - 1) + 1;
} while (i == receiver && players[receiver].isActive);
if (players[receiver].haveBall) {
System.out.println("Player" + i + " passes");
System.out.println("Player" + receiver + " receives");
players[receiver].start();
players[i].join(2000);
players[i].haveBall = false;
players[receiver].haveBall = true;
players[receiver].players = players[0].players;
;
System.out.println();
for (int p = 1; p < n; p++) {
System.out.println(players[p].haveBall);
}
} else {
players[i].haveBall = false;
System.out.println("Player" + i + " passes");
players[receiver].haveBall = true;
System.out.println(players[receiver].number + " receives");
players[receiver].players = players[0].players;
System.out.println();
for (int p = 1; p < n; p++) {
System.out.println(players[p].haveBall);
}
players[receiver].start();
}
}
}
这是一支足球队,我们有两个球,每个球员最多只能有一个球。这些球员在不能将球传给当前有球的球员的情况下随机传球。 我这里有一个for循环,它通过球员循环,选择有球的球员,让他们传球。 我想做的是,如果我们想传给的球员有球,等到他传球,然后把球传给他。但是我为线程编写的join()方法不是这样工作的。(假设每个玩家都是一根线)。最好的解决方案是什么
# 1 楼答案
我会创建一个可供所有工作线程访问的共享资源,一旦一个线程选择了一个资源,他就会使用该资源进行工作,一旦完成,他就会将资源返回到共享资源池
例如,在一个球队列中,球员查询队列以检查是否有球可用,在捡起球时,他们用球进行工作,然后将球放回队列中。这保证了每个球员一次一个球的基本要求
<> P>更多的事情要考虑: