当试图用一个JSONArray解析JSONObject时,java会出现空JSON响应
我得到了获取JSONArrays
的代码,但是当我试图获取只包含一个JSONArray
的JSONObject
时,它会给我空的JSONArray
例如,如果我需要从这个JSONObject
获取数据:
{"events":[{"start":1357714800,"end":1357736400,"name":"Example1","description":""}]}
我将{"events":[]}
作为JSONObject
,[]
表示它不包含任何JSONArray。在本例中,JSONObject
的长度也是0。但它不会抛出任何类型的Exceptions
但是如果JSONObject
包含多个JSONArrays
如下所示:
{"events":[{"start":1357714800,"end":1357736400,"name":"Example1","description":""},{"start":1357714600,"end":1357736500,"name":"Example2","description":""},{"start":1357514800,"end":1357536400,"name":"Example3","description":""}]}
那么我的代码就完美了
下面是我用来解析JSON的代码:
private void getObjects(String url) throws JSONException, Exception {
JSONObject jsonObject = new JSONObject(new NetTask().execute(url).get());
JSONArray job1 = jsonObject.getJSONArray("events");
System.out.println(jsonObject.toString());
System.out.println("JOB1 LENGTH: "+job1.length());
for (int i = 0; i < job1.length(); i++) {
JSONObject jsonEvent = job1.getJSONObject(i);
int start = jsonEvent.getInt("start");
int end = jsonEvent.getInt("end");
String name = jsonEvent.getString("name");
String description = jsonEvent.getString("description");
}
}
public class NetTask extends AsyncTask<String, Integer, String>
{
@Override
protected String doInBackground(String... params)
{
String jsonText = "";
BufferedReader reader = null;
try {
URL url = new URL(params[0]);
reader = new BufferedReader(new InputStreamReader(url.openStream()));
StringBuffer buffer = new StringBuffer();
int read;
char[] chars = new char[1024];
while ((read = reader.read(chars)) != -1) {
buffer.append(chars, 0, read);
}
jsonText = buffer.toString();
} catch (MalformedURLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
return jsonText;
}
}
我是不是遗漏了什么问题,或者这是正常的行为
# 1 楼答案
我尝试了您给定的代码(尽管我只是让AsyncTask只返回单个数组字符串,并且必须用jsonEvent替换opptunti.getString()内容)。getString())。除了您可能正在阻塞UI线程以等待服务器响应之外,它工作得很好
我猜问题在于你点击了错误的URL,参数错误或者类似的东西