java使用安卓中的okhttp在webview中发送每个请求的授权头

Question

我正在使用WebView显示网页，但服务器希望来自我的WebView的每个请求都有一个授权令牌。有人知道这是否可能吗？ 我在#SOadding-header-to-all-request-with-retrofit-2中引用了这篇文章。但是我不能得到结果

这是我的代码（与我的编码标准完全一致，我是初学者）

    public class TableViewTest extends AppCompatActivity {

    ScrollView scrollView;
    WebView webView;
    SharedPreferences pref;

    @SuppressLint("SetJavaScriptEnabled")
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_table_view_test);

        //final ProgressDialog pd = ProgressDialog.show(this, "", "Loading...", true);


        webView = (WebView) findViewById(R.id.webView1Id)

        webView.setVerticalScrollBarEnabled(true);
        webView.setHorizontalScrollBarEnabled(true);
        webView.getSettings().setJavaScriptEnabled(true);
        webView.getSettings().setBuiltInZoomControls(true);

        webView.setWebViewClient(new WebViewClient() {

            @SuppressWarnings("deprecation")
            @Override
            public boolean shouldOverrideUrlLoading(WebView view, String url) {
                //return true load with system-default-browser or other browsers, false with your webView

                pref = getSharedPreferences("app", Context.MODE_PRIVATE);
                final String acToken = pref.getString("token", "DEFAULT");


                HashMap<String, String> headerMap = new HashMap<>();
                //put all headers in this header map
                headerMap.put("Authorization", acToken);


                view.loadUrl(url, headerMap);


                return false;
            }

            @Override
            public void onLoadResource(WebView view, String url) {
                super.onLoadResource(view, url);
            }

            @Override
            public void onPageStarted(WebView view, String url, Bitmap favicon) {
                super.onPageStarted(view, url, favicon);
            }
        });

        webView.loadUrl("myurl");

    }


    @Override
    protected void onSaveInstanceState(Bundle outState) {
        super.onSaveInstanceState(outState);
        webView.saveState(outState);
    }

    @Override
    protected void onRestoreInstanceState(Bundle savedInstanceState) {
        super.onRestoreInstanceState(savedInstanceState);
        webView.restoreState(savedInstanceState);
    }


    public WebViewClient getWebViewClientWithCustomHeader(){

        pref = getSharedPreferences("app", Context.MODE_PRIVATE);
        final String acToken = pref.getString("token", "DEFAULT");

        return new WebViewClient() {

            @SuppressWarnings("deprecation")
            public WebResourceResponse shouldInterceptRequest(WebView view, String url){
                try {
                    OkHttpClient okHttpClient = new OkHttpClient();
                    Request request = new Request.Builder().url(url).addHeader("Authorization" , "Bearer " + acToken)
                            .build();

                    Response response = okHttpClient.newCall(request).execute();

                    return new WebResourceResponse(response.header("content-type", response.body().contentType().type()), // You can set something other as default content-type
                            response.header("content-encoding", "utf-8"),  // Again, you can set another encoding as default
                            response.body().byteStream());


                } catch (ClientProtocolException e) {
                    //return null to tell WebView we failed to fetch it WebView should try again.
                    return null;
                } catch (IOException e) {
                    e.printStackTrace();
                    return null;
                }
            }
        };
    }
}

谢谢你的帮助

编辑

现在我能够得到服务器的响应，但是在纯html中，没有正确地呈现css，我不知道为什么

这是新代码

    public class TableViewTest extends AppCompatActivity {

    ScrollView scrollView;
    WebView webView;
    SharedPreferences pref;

    @SuppressLint("SetJavaScriptEnabled")
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_table_view_test);

        //final ProgressDialog pd = ProgressDialog.show(this, "", "Loading...", true);

        String url = "myurl";
        pref = getSharedPreferences("app", Context.MODE_PRIVATE);


        webView = (WebView) findViewById(R.id.webView1Id);

        webView.setVerticalScrollBarEnabled(true);
        webView.setHorizontalScrollBarEnabled(true);
        webView.getSettings().setJavaScriptEnabled(true);
        webView.getSettings().setBuiltInZoomControls(true);
        webView.setWebViewClient(wvc);

        webView.loadUrl("myurl");

    }


    @Override
    protected void onSaveInstanceState(Bundle outState) {
        super.onSaveInstanceState(outState);
        webView.saveState(outState);
    }

    @Override
    protected void onRestoreInstanceState(Bundle savedInstanceState) {
        super.onRestoreInstanceState(savedInstanceState);
        webView.restoreState(savedInstanceState);
    }


    public WebViewClient wvc =  new WebViewClient() {

            @SuppressWarnings("deprecation")
            public WebResourceResponse shouldInterceptRequest(WebView view, String url){
                try {
                    final String acToken = pref.getString("token", "DEFAULT");

                    OkHttpClient okHttpClient = new OkHttpClient();
                    Request request = new Request.Builder().url(url).addHeader("Authorization" , "Bearer " + acToken)
                            .build();

                    Response response = okHttpClient.newCall(request).execute();

                    return new WebResourceResponse(response.header("content-type", response.body().contentType().type()), // You can set something other as default content-type
                            response.header("content-encoding", "utf-8"),  // Again, you can set another encoding as default
                            response.body().byteStream());


                } catch (ClientProtocolException e) {
                    //return null to tell WebView we failed to fetch it WebView should try again.
                    return null;
                } catch (IOException e) {
                    e.printStackTrace();
                    return null;
                }
            }
        };
}

在stacktrace中找到了这个，在stacktrace中没有更多

 E/DataReductionProxySettingListener: No DRP key due to exception:java.lang.ClassNotFoundException: com.安卓.webview.chromium.Drp

Answer 1

最后，这将纠正html呈现问题（对不起，我之前没有注意到这一点）

更改中的content-type

return new WebResourceResponse(response.header("content-type", response.body().contentType().type()), // You can set something other as default content-type
                        response.header("content-encoding", "utf-8"),  // Again, you can set another encoding as default
                        response.body().byteStream());

到text/html，因此新代码是

return new WebResourceResponse(response.header("text/html", response.body().contentType().type()), // You can set something other as default content-type
                    response.header("content-encoding", "utf-8"),  // Again, you can set another encoding as default
                    response.body().byteStream());

如果我的解决方案需要任何修改，请随意编辑。总是接受更好的解决方案。快乐编码。。。感谢所有愿意帮忙的人

Answer 2

Sudheesh的回答很好，以下是更新版本，因为shouldOverrideUrlLoading(WebView view, String url)在API 21中被弃用：

webView.setWebViewClient(new WebViewClient() {
            public WebResourceResponse shouldInterceptRequest(WebView view, WebResourceRequest webResourceRequest) {
                // Filter out any requests we not interested in
                if (webResourceRequest.getUrl().getHost() == null ||
                        !webResourceRequest.getUrl().getHost().equals(MyAPI.getServer().toHost())) {
                    return super.shouldInterceptRequest(view, webResourceRequest);
                }
                try {
                    OkHttpClient okHttpClient = new OkHttpClient();
                    Request request = new Request.Builder().url(webResourceRequest.getUrl().toString())
                            .addHeader(HttpConnector.DefaultConnector().getAuthorizationHeaderKey(), HttpConnector.DefaultConnector().getAuthorizationHeaderValue())
                            .build();
                    Response response = okHttpClient.newCall(request).execute();
                    return new WebResourceResponse(response.header("text/html", response.body().contentType().type()), // You can set something other as default content-type
                            response.header("content-encoding", "utf-8"),  // Again, you can set another encoding as default
                            response.body().byteStream());
                } catch (ClientProtocolException e) {
                    //return null to tell WebView we failed to fetch it WebView should try again.
                    return null;
                } catch (IOException e) {
                    e.printStackTrace();
                    return null;
                }
            }
        });

Answer 3

这可能不能回答你的问题，但我认为这对其他有类似问题的人会有帮助

如果服务器资源需要这样的基本身份验证头Authorization: Basic dXNlcm5hbWU6cGFzc3dvcmQ=，那么您应该像这样重写WebViewClient中的onReceivedHttpAuthRequest方法

webView.webViewClient = object : WebViewClient() {

    override fun onReceivedHttpAuthRequest(view: WebView?, handler: HttpAuthHandler?, host: String?, realm: String?) {
        handler?.proceed("username", "password")
    }

}

还请注意，如果可能，您应该始终避免拦截WebView请求。阅读更多关于它的信息here