spring boot Elasticsearch高级Rest客户端Java排序工作不正常
我是Elasticsearch高级Rest客户端（Java）的新手
我有一个非常简单的查询，其中列出了所有记录，但排序似乎没有正常工作
有些字段是文本类型，所以我需要将fielddata设置为true
更新：
谢谢安德烈的解决方案
我需要添加另一个字段，它是对象数组user.groups
我将.keyword添加到可排序的映射字段（文本）
但我得到了意想不到的结果
示例：
...
"groups": [
{"name", "ECPay", ... },
{"name", "Abangers", ... }
]
...
根据下面的输出，如果有两个组项ECPay和Abangers。。。使用^ {CD5> }排序将考虑abanges。
我想把^ {CD1>}数组的第一个元素作为排序的基础。
根据上面的示例，tt将使用ECPay作为排序的基础，因为它是数组的第一个元素
要了解问题（更新），让我们检查下面的搜索结果（排序）
搜索结果（输出）：
{
"took": 18,
"timed_out": false,
"_shards": {
"total": 5,
"successful": 5,
"skipped": 0,
"failed": 0
},
"hits": {
"total": 74,
"max_score": null,
"hits": [
{
"_index": "acme_users",
"_type": "user",
"_id": "5",
"_score": null,
"_source": {
"name": "Ericsson Joseph Sultan Atutuli",
"country": "",
"uuid": "5",
"userId": 5,
"email": "ejsultanatutuli@gmail.com",
"deletedInd": false,
"groups": [
{
"name": "ECPay",
"id": 2
},
{
"name": "Abangers",
"id": 4
}
],
"company": ""
},
"sort": [
"Abangers"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "54",
"_score": null,
"_source": {
"name": "Florentina Atutuli",
"country": null,
"uuid": "54",
"userId": 54,
"email": "florentina.atutuli@gmail.com",
"deletedInd": false,
"groups": [
{
"name": "Abangers",
"id": 4
},
{
"name": "Test Group",
"id": 5
}
],
"company": null
},
"sort": [
"Abangers"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "37",
"_score": null,
"_source": {
"name": "dsfsdfsdf",
"country": null,
"uuid": "37",
"userId": 37,
"email": "asdf@sdf.com",
"deletedInd": false,
"groups": [
{
"name": "Abangers",
"id": 4
},
{
"name": "Test Group",
"id": 5
}
],
"company": null
},
"sort": [
"Abangers"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "3",
"_score": null,
"_source": {
"name": "Erick Atutuli",
"country": "Philippines",
"email": "erickatutuli@pakyas.com",
"userId": 3,
"uuid": "d8f4ab43-d33e-4a82-a08b-eb73342a0546",
"groups": [
{
"name": "ECPay",
"id": 2
},
{
"name": "Abangers",
"id": 4
}
],
"deletedInd": false,
"company": "Hotlegs Incorporated"
},
"sort": [
"Abangers"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "34",
"_score": null,
"_source": {
"name": "Chun-Li",
"country": null,
"email": "chunli@pakyas.com",
"uuid": "34",
"userId": 34,
"deletedInd": false,
"groups": [
{
"name": "Customers AU",
"id": 1
}
],
"company": null
},
"sort": [
"Customers AU"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "57",
"_score": null,
"_source": {
"name": "Eddy Bear",
"country": "US",
"email": "eddybear@pakyas.com",
"uuid": "57",
"userId": 57,
"deletedInd": false,
"groups": [
{
"name": "Customers AU",
"id": 1
}
],
"company": "Jollibee"
},
"sort": [
"Customers AU"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "42",
"_score": null,
"_source": {
"name": "Alfredo Pitik Mingaw",
"country": "",
"email": "akomykel@gmail.com",
"userId": 42,
"uuid": "42",
"deletedInd": false,
"groups": [
{
"name": "ECPay",
"id": 2
}
],
"company": ""
},
"sort": [
"ECPay"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "20",
"_score": null,
"_source": {
"name": "test",
"country": "Åland Islands",
"userId": 20,
"email": "test102@email.com",
"uuid": "20",
"groups": [
{
"name": "ECPay",
"id": 2
}
],
"deletedInd": false,
"company": "test"
},
"sort": [
"ECPay"
]
},
...
]
}
}
现在，我在用户映射中添加了keyword字段：
...
"groups": {
"properties": {
"name": {
"type": "text",
"fields": {
"keyword": {
"type": "keyword",
"ignore_above": 256
}
}
}
}
},
...
使文本字段可排序，删除字段数据并添加关键字
http://localhost:9200/acme_users/_mapping/user
{
"properties": {
"name": {
"type": "text",
"fields": {
"keyword": {
"type": "keyword",
"ignore_above": 256
}
}
},
"company": {
"type": "text",
"fielddata": true
},
"country": {
"type": "text",
"fielddata": true
},
"groups": {
"properties": {
"name": {
"type": "text",
"fields": {
"keyword": {
"type": "keyword",
"ignore_above": 256
}
}
}
}
},
"email": {
"type": "text",
"fields": {
"keyword": {
"type": "keyword",
"ignore_above": 256
}
}
}
}
}
下面的查询是从我的Java应用程序（Spring）生成的
这是一个非常简单的例子，我只是将结果按nameascending顺序排序
查询
将.keyword添加到排序字段。在下面的示例中。。。它将使用groups.name.keyword进行排序，它最初是groups.name
http://localhost:9200/acme_users/user/_search
{
"from" : 0,
"size" : 15,
"query" : {
"match_all" : {
"boost" : 1.0
}
},
"sort" : [
{
"groups.name.keyword" : {
"order" : "asc"
}
}
]
}
原始问题：
但我现在的问题是，似乎ES排序不能正常工作。当我将顺序从asc更改为desc（反之亦然）时，结果会发生变化
虽然结果发生了变化，但名称（result）似乎没有正确排序（a-z）或（z-a）
似乎它得到了name的最后一部分，并将其用作排序的基础。我想基于name的第一个字符值
原始搜索结果：
{
"took": 4,
"timed_out": false,
"_shards": {
"total": 5,
"successful": 5,
"skipped": 0,
"failed": 0
},
"hits": {
"total": 73,
"max_score": null,
"hits": [
{
"_index": "acme_users",
"_type": "user",
"_id": "22",
"_score": null,
"_source": {
"name": "Popeye Partner 01",
"country": null,
"userId": 22,
"email": "popeye_partner_01@kugmo.com",
"uuid": "22",
"deletedInd": false,
"company": null
},
"sort": [
"01"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "24",
"_score": null,
"_source": {
"name": "Dummy User 01",
"country": null,
"userId": 24,
"email": "dummy@dummy.com",
"uuid": "24",
"deletedInd": false,
"company": null
},
"sort": [
"01"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "23",
"_score": null,
"_source": {
"name": "Popeye Partner 02",
"country": null,
"userId": 23,
"email": "popeye_partner_02@kugmo.com",
"uuid": "23",
"deletedInd": false,
"company": null
},
"sort": [
"02"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "25",
"_score": null,
"_source": {
"name": "RT Administrator",
"country": null,
"userId": 25,
"email": "rt_administrator@kugmo.com",
"uuid": "25",
"deletedInd": false,
"company": null
},
"sort": [
"administrator"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "48",
"_score": null,
"_source": {
"name": "John Patrick Abnoy",
"country": null,
"userId": 48,
"email": "patrickabnoy@gmail.com",
"uuid": "48",
"deletedInd": false,
"company": null
},
"sort": [
"abnoy"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "5",
"_score": null,
"_source": {
"name": "Ericsson John Santol Atutuli",
"country": "",
"uuid": "5",
"userId": 5,
"email": "ejsantolatutuli@gmail.com",
"deletedInd": false,
"company": ""
},
"sort": [
"atutuli"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "54",
"_score": null,
"_source": {
"name": "Florentina Atutuli",
"country": null,
"uuid": "54",
"userId": 54,
"email": "florentina.atutuli@gmail.com",
"deletedInd": false,
"company": null
},
"sort": [
"atutuli"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "49",
"_score": null,
"_source": {
"name": "Laarnie Santol Atutuli",
"country": "",
"email": "lmsantolatutuli@gmail.com",
"userId": 49,
"uuid": "49",
"deletedInd": false,
"company": ""
},
"sort": [
"atutuli"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "3",
"_score": null,
"_source": {
"name": "Eric Atutuli",
"country": "Philippines",
"uuid": "d8f4ab43-d33e-4a82-a08b-eb73342a0546",
"userId": 3,
"email": "ericatutuli@kugmo.com",
"deletedInd": false,
"company": "Hotlegs Incorporated"
},
"sort": [
"atutuli"
]
},
{
"_index": "acme_users",
"_type": "user",
"_id": "29",
"_score": null,
"_source": {
"name": "Auberto Matulis",
"country": null,
"userId": 29,
"email": "bert.matulis@gmail.com",
"uuid": "29",
"deletedInd": false,
"company": null
},
"sort": [
"auberto"
]
}
]
}
}
谢谢
# 1 楼答案
name是一个text字段，表示已对其进行分析。分析意味着它被分割成代币。如果将Popeye Partner 01拆分为popeye、partner、01您希望使用哪个字段进行排序？可能没有，因为您希望对原始文本进行排序。为此，请在name字段中添加一个子字段然后在查询中使用它进行排序：
# 2 楼答案
我们遇到了同样的问题，然后我们查看了我们在indexCreation时创建的映射，我们观察到了一些事情
"fielddata": true（尽可能避免此操作，因为它会占用堆内存）"type":"keyword""type":"long"或
"type": "scaled_float", "scaling_factor": 100