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JavaSpringBootRestTemplate。postForObject参数为空

我有两个spring boot应用程序,一个作为前端运行,另一个作为后端服务运行。从前端我对后端服务进行api调用,我发送的两个参数都显示为null。我认为问题在于rest模板

更新

所以我注意到,如果我省略了内容值,那么它就会起作用。由于内容是大于1mb的文件的内容,我在应用程序中添加了以下内容。yml:

spring.servlet.multipart.max-file-size: 10MB
spring.servlet.multipart.max-request-size: 10MB

以下是我的代码,我在本期中发布的代码基础上进行了更新: How to POST form data with Spring RestTemplate?

但是我仍然没有在后端控制器中获取值,而是两个值都为null

        public void upload(byte[] content, String name) {
        String encodedString = Base64.getEncoder().encodeToString(content);
        HttpHeaders headers = new HttpHeaders();
        headers.setContentType(MediaType.APPLICATION_FORM_URLENCODED);

        MultiValueMap<String, String> map = new LinkedMultiValueMap<String, String>();
        map.add("fileName", name);
        map.add("content", encodedString);

        HttpEntity<MultiValueMap<String, String>> request = new HttpEntity<MultiValueMap<String, String>>(map, headers);

        ResponseEntity<String> response = restTemplate.postForEntity(backendUrl + "/upload", request, String.class);
        log.debug("Response from upload: " + response);
    }

这是后端的控制器。文件名和内容均为空:

        @CrossOrigin
    @SneakyThrows
    @ResponseBody
    @PostMapping(value = "/upload")
    public ResponseEntity<String> upload(@ModelAttribute FormModel form) {
        byte[] decodedBytes = Base64.getDecoder().decode(form.getContent());
        uploadService.upload(decodedBytes, form.getFileName());
        HttpHeaders responseHeaders = new HttpHeaders();
        responseHeaders.set("Content-Type", "application/json");
        return ResponseEntity.ok().headers(responseHeaders).body("Uploaded");
    }

谁能看看这个代码有什么问题吗

提前谢谢


共 (2) 个答案

  1. # 1 楼答案

    我想问题是您试图使用restTemplate.postForObject,但是使用@RequestParam而不是@RequestBody

    @RequestParam中,您希望在查询参数/upload?fileName=&content=中接收数据。但是你实际上是用restTemplate.postForObject(backendService+ "/upload", map, String.class);在身体里发送它

    所以我的建议是改变

    public ResponseEntity<String> upload(@RequestParam(value = "fileName") String fileName, @RequestParam(value = "content") String content)

    public ResponseEntity<String> upload(@RequestBody Map<String, String> body)

    然后从正文中获取文件名和文件内容

  2. # 2 楼答案

    好的,我可以通过发送和接收字节而不是编码为字符串的字节来修复它。 因此,在resttemplate中:

        public void upload(byte[] bytes, String name) {
            HttpHeaders headers = new HttpHeaders();
            headers.setContentType(MediaType.MULTIPART_FORM_DATA);
    
            MultiValueMap<String, Object> map = new LinkedMultiValueMap<String, Object>();
            map.add("fileName", name);
            map.add("bytes", bytes);
    
            HttpEntity<MultiValueMap<String, Object>> request = new HttpEntity<MultiValueMap<String, Object>>(map, headers);
            log.debug("map values: " + map.toString());
    
            ResponseEntity<String> response = restTemplate.postForEntity(backendUrl + "/upload", request, String.class);
            log.debug("Response from upload: " + response);
        }
    
    

    在控制器中:

    public ResponseEntity<String> upload(@ModelAttribute FormModel form) {
            byte[] bytes = form.getBytes();
            uploadService.upload(bytes, form.getFileName());
            HttpHeaders responseHeaders = new HttpHeaders();
            responseHeaders.set("Content-Type", "application/json");
            return ResponseEntity.ok().headers(responseHeaders).body("Uploaded");
        }
    

    不过,如果能知道为什么以前的版本不起作用,那就太好了