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Android中的java解析动态json对象

我正在尝试解析下面的json,并使用BaseAdapterAndroid在ListView中显示它。这里的对象41动态的。如果这些值不是动态的,我知道如何创建模型类。我尝试使用以下方法获取json,但它不返回任何值Model.java中有什么错误吗?还是应该更改json的格式

         {  
   "effect_list":[  
      {  
         "4":[  
            {  
               "effects_id":"18",
               "effects_name":"Band 1"
            },
            {  
               "effects_id":"19",
               "effects_name":"Band 2"
            }
         ],
         "1":[  
            {  
               "effects_id":"1",
               "effects_name":"Background Blur"
            },
            {  
               "effects_id":"4",
               "effects_name":"Blemish Removal"
            }
         ]
      }
   ]
}

模型。java

public class Model{


@SerializedName("effect_list")
@Expose
List<Map<String,List<EffectList>>>  effectlist;

public List<Map<String, List<EffectList>>> getEffectlist() {
    return effectlist;
}

public void setEffectlist(List<Map<String, List<EffectList>>> effectlist) {
    this.effectlist = effectlist;
}
}

效应列表。java

public class EffectList {



@SerializedName("effects_id")
@Expose
private String effectsId;

@SerializedName("effects_name")
@Expose
private String effectsName;



 //GETTERS AND SETTERS


} 

mycontactadapter 2。java

public class MyContactAdapter2 extends BaseAdapter {


    ArrayList<Map<String, List<EffectList>>> contactList;
    Context context;
    private LayoutInflater mInflater;

public MyContactAdapter2(Context context, ArrayList<Map<String, List<EffectList>>> data) {      
    this.context = context;
    this.mInflater = LayoutInflater.from(context);
    contactList = data;


}


@Override
public int getCount() {
    return 0;
}

@Override
public List<HashMap<String, List<EffectList>>> getItem(int position) {
    return (List<HashMap<String, List<EffectList>>>) contactList.get(position);
}

@Override
public long getItemId(int i) {
    return 0;
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    final ViewHolder1 vh1;
    if (convertView == null) {
        View view = mInflater.inflate(R.layout.get_layout_row_view, parent, false);
        vh1 = ViewHolder1.create((RelativeLayout) view);
        view.setTag(vh1);
    } else {
        vh1 = (ViewHolder1) convertView.getTag();
    }


    EffectList item = (EffectList) getItem(position);


    //   vh.textViewName.setText(item.getEffectsId());


    vh1.textViewName.setText(item.getEffectsName());
    vh1.textViewEmail.setText(item.getEffectsId());

    // Picasso.with(context).load(item.getProfilePic()).placeholder(R.mipmap.ic_launcher).error(R.mipmap.ic_launcher).into(vh.imageView);

    return vh1.rootView;
}


private static class ViewHolder1 {
    public final RelativeLayout rootView;
    public final ImageView imageView;
    public final TextView textViewName;
    public final TextView textViewEmail;

    private ViewHolder1(RelativeLayout rootView, ImageView imageView, TextView textViewName, TextView textViewEmail) {
        this.rootView = rootView;
        this.imageView = imageView;
        this.textViewName = textViewName;
        this.textViewEmail = textViewEmail;
    }

    public static MyContactAdapter2.ViewHolder1 create(RelativeLayout rootView) {
        ImageView imageView = (ImageView) rootView.findViewById(R.id.imageView);
        TextView textViewName = (TextView) rootView.findViewById(R.id.textViewName);
        TextView textViewEmail = (TextView) rootView.findViewById(R.id.textViewEmail);
        return new MyContactAdapter2.ViewHolder1(rootView, imageView, textViewName, textViewEmail);
    }
}


}

MyContactAdapter2有什么问题吗


共 (3) 个答案

  1. # 1 楼答案

    Have a look at this

    我在使用GSON解析时也遇到了同样的问题,但通过使用StringRequest实现<&燃气轮机;而不是GSONRequest<&燃气轮机; 请核对我的答案

  2. # 2 楼答案

    您可以从本网站的JSON创建POJO Model class

    http://www.jsonschema2pojo.org/

    这是我用你的json做的!虽然你的json应该更简单

    -com。实例效应列表。爪哇-

    package com.example;
    
    import java.util.List;
    import com.google.gson.annotations.Expose;
    import com.google.gson.annotations.SerializedName;
    
    public class EffectList {
    
    @SerializedName("4")
    @Expose
    private List<com.example._4> _4 = null;
    @SerializedName("1")
    @Expose
    private List<com.example._1> _1 = null;
    
    public List<com.example._4> get4() {
    return _4;
    }
    
    public void set4(List<com.example._4> _4) {
    this._4 = _4;
    }
    
    public List<com.example._1> get1() {
    return _1;
    }
    
    public void set1(List<com.example._1> _1) {
    this._1 = _1;
    }
    
    }
                     -com.example.Example.java                 -
    
    package com.example;
    
    import java.util.List;
    import com.google.gson.annotations.Expose;
    import com.google.gson.annotations.SerializedName;
    
    public class Example {
    
    @SerializedName("effect_list")
    @Expose
    private List<EffectList> effectList = null;
    
    public List<EffectList> getEffectList() {
    return effectList;
    }
    
    public void setEffectList(List<EffectList> effectList) {
    this.effectList = effectList;
    }
    
    }
                     -com.example._1.java                 -
    
    package com.example;
    
    import com.google.gson.annotations.Expose;
    import com.google.gson.annotations.SerializedName;
    
    public class _1 {
    
    @SerializedName("effects_id")
    @Expose
    private String effectsId;
    @SerializedName("effects_name")
    @Expose
    private String effectsName;
    
    public String getEffectsId() {
    return effectsId;
    }
    
    public void setEffectsId(String effectsId) {
    this.effectsId = effectsId;
    }
    
    public String getEffectsName() {
    return effectsName;
    }
    
    public void setEffectsName(String effectsName) {
    this.effectsName = effectsName;
    }
    
    }
                     -com.example._4.java                 -
    
    package com.example;
    
    import com.google.gson.annotations.Expose;
    import com.google.gson.annotations.SerializedName;
    
    public class _4 {
    
    @SerializedName("effects_id")
    @Expose
    private String effectsId;
    @SerializedName("effects_name")
    @Expose
    private String effectsName;
    
    public String getEffectsId() {
    return effectsId;
    }
    
    public void setEffectsId(String effectsId) {
    this.effectsId = effectsId;
    }
    
    public String getEffectsName() {
    return effectsName;
    }
    
    public void setEffectsName(String effectsName) {
    this.effectsName = effectsName;
    }
    
    }
    
  3. # 3 楼答案

    我认为你应该改变这种方法

    @Override
    public int getCount() {
        return contactList.size();
    }
    

    希望这有帮助