Java for正在跳过的循环
import java.lang.Integer;
import java.util.Arrays;
public class Decimal {
//initialize intance variables
private int decimal;
private String hex;
public static void toHex(String s) {
int decimal = Integer.parseInt(s); //converts the s string into an int for binary conversion.
String hex = null;
int[] binNum = new int[16];
int[] binNumNibble = new int[4]; //A nibble is four bits.
int nibbleTot = 0;
char hexDig = '\0';
char[] cvtdHex = new char[4];
StringBuffer result = new StringBuffer();
for(int a = 32768; a == 1; a /= 2) { //32768 is the value of the largest bit.
int b = 0;//Will top at 15 at the end of the for loop. 15 references the last spot in the binNum array.
if(decimal > a) {
decimal -= a;
binNum[b++] = 1;//Arrays have a default value of zero to all elements. This provides a parsed binary number.
}
}
for(int a = 0; a == 15; a += 3) {
//Copies pieces of the binary number to the binNumNibble array. .arraycopy is used in java 1.5 and lower.
//Arrays.copyOfRange is used in java 1.5 and higher.
System.arraycopy(binNum, a, binNumNibble, 0, 4);
for(int b = 8; b == 1; a += 3) {
int c = 0;
nibbleTot += binNumNibble[c++];
//Converts the single hex value into a hex digit.
if(nibbleTot >= 1 && nibbleTot <= 9) {
hexDig += nibbleTot;
} else if(nibbleTot == 10) {
hexDig = 'A';
} else if(nibbleTot == 11) {
hexDig = 'B';
} else if(nibbleTot == 12) {
hexDig = 'C';
} else if(nibbleTot == 13) {
hexDig = 'D';
} else if(nibbleTot == 14) {
hexDig = 'E';
} else if(nibbleTot == 15) {
hexDig = 'F';
}
cvtdHex[c++] = hexDig;
}
}
//return hex = new String(cvtdHex);
hex = new String(cvtdHex);
System.out.print("Hex: " + hex);
}
}
我似乎不明白为什么变量hex作为空白变量返回。我一直在使用这个系统。出来打印();在每个for循环中,都没有使用它们,这给我的印象是for循环被完全跳过了,但我不明白为什么,我有时间限制
非常感谢您的帮助,但请不要只是粘贴代码。我需要在我的计算机科学课上理解这一点
# 1 楼答案
怎么样
# 2 楼答案
由于双
==
,因此for loops
不会执行# 3 楼答案
是的,将跳过for循环,因为for语句的第二部分不是break条件,而是必须完全填充才能运行循环的条件
事实并非如此
但是
等等