java OutOfMemory错误需要解决

Question

我知道使用位图是一个常见的问题，但我不知道如何使用这个示例。特别是因为图像视图的大小不大，所以您会说它应该会导致内存错误。我想这是因为我经常创建位图，而不是创建一次，每五秒钟显示一次，但不知道怎么做。首先是创建位图的代码

java类trapViews：

@Override
protected void onDraw(Canvas canvas) {
    super.onDraw(canvas);
    int x = 20;
    Random r = new Random();
    int i1 = r.nextInt(900 - 200) + 200;
    rnd = new Random();
    //Linke Seite

    System.gc();

    Bitmap image = BitmapFactory.decodeResource(getResources(), R.drawable.stachelnstart);
    Bitmap resizedBitmap = Bitmap.createScaledBitmap(image, i1, 300, true);
        float left = (float) 0;
        float top = (float) (getHeight() - resizedBitmap.getHeight());
        canvas.drawBitmap(resizedBitmap, left, top, paint);

        //rechte Seite
        Bitmap images = BitmapFactory.decodeResource(getResources(), R.drawable.stachelnstart1);
        Bitmap resizedBitmaps = Bitmap.createScaledBitmap(images, getWidth()-resizedBitmap.getWidth()-OwlHole, 300, true);
        float left1 = (float) (getWidth() - resizedBitmaps.getWidth());
        float top1 = (float) (getHeight() - resizedBitmaps.getHeight());
        canvas.drawBitmap(resizedBitmaps, left1, top1, paint);
    }
}

在屏幕的右侧和左侧创建具有随机长度的可绘制图形

现在我在MainActivity中每隔5秒用Handler调用一次：

final Handler h = new Handler();
Runnable r = new Runnable() {
    public void run() {
        System.gc();
        traps();
        h.postDelayed(this,5000); // Handler neustarten
    }
}

private void traps() {
    container = (ViewGroup) findViewById(R.id.container);
    trapViews tv = new trapViews(this);
    container.addView(tv,
        ViewGroup.LayoutParams.MATCH_PARENT,
        ViewGroup.LayoutParams.MATCH_PARENT);
    //tV.setImageCount(8);
    h.postDelayed(r, 5000);
}

首先，它工作起来就像我希望它工作一样。但每次出现一个新的抽绳器，我的游戏就落后了，在创造了5-6次抽绳器之后，它就崩溃了

System.gc()和bitmap.recycle函数工作得不是很好。有人有解决办法吗

Answer 1

您每5秒创建一次位图，这不是一个好主意，因为它们总是一样的。您应该创建它们一次

 trapViews extends View{
    Bitmap image;
        Bitmap resizedBitmap;


        //rechte Seite
       Bitmap images ;
        Bitmap resizedBitmaps;

trapViews(Context c){
image = BitmapFactory.decodeResource(getResources(), R.drawable.stachelnstart);
images = BitmapFactory.decodeResource(getResources(), R.drawable.stachelnstart1);

}

@Override
protected void onDraw(Canvas canvas) {
        super.onDraw(canvas);
        int x = 20;
        Random r = new Random();
        int i1 = r.nextInt(900 - 200) + 200;
        rnd = new Random();
        //Linke Seite
          //I have left this bitmap in the here as it is affected by the random int
         resizedBitmap = Bitmap.createScaledBitmap(image, i1, 300, true);
            float left = (float) 0;
            float top = (float) (getHeight() - resizedBitmap.getHeight());
            canvas.drawBitmap(resizedBitmap, left, top, paint);

          //create this bitmap here as getWidth() will return 0 if created in the view's constructor
        if(resizedBitmaps == null)
         resizedBitmaps = Bitmap.createScaledBitmap(images, getWidth()-resizedBitmap.getWidth()-OwlHole, 300, true);
            float left1 = (float) (getWidth() - resizedBitmaps.getWidth());
            float top1 = (float) (getHeight() - resizedBitmaps.getHeight());
            canvas.drawBitmap(resizedBitmaps, left1, top1, paint);

}


}

Answer 2

记得调用位图。替换位图后或位图不再可见时回收（）。 创建多个位图不是问题，而是在不使用回收来释放内存的情况下保留未使用的对象