java将一个句子拆分为字符串数组，并保留特殊字符或空格

Question

我想把一个有空格或任何特殊字符的句子分成一个单词数组，其中空格或特殊字符也是数组的一个元素

像这样的句子：

aman,amit and sumit went to top-up 

应拆分为字符串数组：

{"aman",",","amit"," ","and"," ","sumit"," ","went"," ","to"," ","top","-","up")

请建议使用任何正则表达式或逻辑来使用java进行拆分

我的问题遗漏了一件事。我还需要拆分数字字符。。但是使用split（“\b”）不会拆分具有以下内容的字符串

abc12def

进入

{ "abc", "12","def") or {"abc","1","2","def")

Answer 1

我希望下面的代码片段能帮助您解决这个问题

public static void main(final String[] args) {
        String message = "aman,amit and sumit went to top-up";
        String[] messages = message.split("\\b");
        for(String string : messages) {
            System.out.println(string);
        }
    }

Answer 2

似乎您只需要匹配单词字符（\w+）或非单词字符（\W+）。将它们与一个交替操作符结合起来，并-也许-添加一个Pattern.UNICODE_CHARACTER_CLASS（或其内联/嵌入版本(?U)），以使模式能够识别Unicode：

String value = "aman,amit and sumit went to top-up";
String pattern = "(?U)\\w+|\\W+";
List<String> lst = new ArrayList<>();
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(value);
while (m.find())
    lst.add(m.group(0));
System.out.println(lst);

见Java demo