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[QueryDSL/Spring]java。lang.IllegalStateException:连接不是事务性的

我正在编写Spring+Vaadin应用程序。我想将QueryDSL添加到access db(Oracle)中。我查阅了文档(http://docs.spring.io/spring-data/jdbc/docs/current/reference/html/core.querydsl.html),了解到Spring建议使用标准QueryDSLAPI。我在以下情况下加入了我的项目:

<dependency>
    <groupId>com.mysema.querydsl</groupId>
    <artifactId>querydsl-sql-spring</artifactId>
    <version>${querydsl.version}</version>
</dependency>
<dependency>
    <groupId>org.springframework</groupId>
    <artifactId>spring-jdbc</artifactId>
    <version>${spring.version}</version>
</dependency>
<dependency>
    <groupId>org.apache.commons</groupId>
    <artifactId>commons-dbcp2</artifactId>
    <version>2.1.1</version>
</dependency>
<dependency>
    <groupId>com.mysema.querydsl</groupId>
    <artifactId>querydsl-sql</artifactId>
    <version>${querydsl.version}</version>
</dependency>

我的豆子。xml如下所示:

<bean id="dataSourceOracle" class="org.apache.commons.dbcp2.BasicDataSource" destroy-method="close">
    <property name="driverClassName" value="${db.oracle.driverClassName}" />
    <property name="url" value="${db.oracle.url}"/>
    <property name="username" value="${db.oracle.username}" />
    <property name="password" value="${db.oracle.password}" />
    <property name="defaultAutoCommit" value="false" />
</bean>

在我的DatabaseFacade实现中,我执行以下配置:

private SQLQueryFactory query;

@Autowired
@Qualifier("DataSource")
public void setDataSource(DataSource dataSource) {
    Provider<Connection> provider = new SpringConnectionProvider(dataSource);
    Configuration configuration = new Configuration(new OracleTemplates());
    configuration.setExceptionTranslator(new SpringExceptionTranslator());
    query = new SQLQueryFactory(configuration, provider);
}

不幸的是,每次启动应用程序时,我都会得到:

10:29:54.490 [main] DEBUG o.s.jdbc.datasource.DataSourceUtils - Fetching JDBC Connection from DataSource
10:29:56.231 [main] ERROR c.r.i.k.b.impl.DatabaseFacadeImpl - Error happend in com.roche.icc.kps.backend.impl.DatabaseFacadeImpl.getEditableKPSStores
10:29:56.234 [main] ERROR c.r.i.k.b.impl.DatabaseFacadeImpl - Connection is not transactional
java.lang.IllegalStateException: Connection is not transactional
    at com.mysema.query.sql.spring.SpringConnectionProvider.get(SpringConnectionProvider.java:45) ~[querydsl-sql-spring-3.7.0.jar:na]
    at com.mysema.query.sql.spring.SpringConnectionProvider.get(SpringConnectionProvider.java:33) ~[querydsl-sql-spring-3.7.0.jar:na]
    at com.mysema.query.sql.SQLQueryFactory.query(SQLQueryFactory.java:63) ~[querydsl-sql-3.7.0.jar:na]
    at com.mysema.query.sql.SQLQueryFactory.query(SQLQueryFactory.java:28) ~[querydsl-sql-3.7.0.jar:na]
    at com.mysema.query.sql.AbstractSQLQueryFactory.from(AbstractSQLQueryFactory.java:54) ~[querydsl-sql-3.7.0.jar:na]

有人遇到过这个问题吗?我应该使用不同的DataSource(Atomikos?)吗

谢谢你的帮助

卡米尔


共 (2) 个答案

  1. # 1 楼答案

    我遇到了此问题,并能够解决此问题,如下所示:

    除了应该为dao/Repository类标记@Transactional注释外,还必须为spring java配置类标记@EnableTransactionManagement,如下所示

    @Configuration
    @EnableTransactionManagement
    public class QuerydslConfiguration {
        @Bean
        public DataSource dataSource() {
            // implement your datasource
        }
    
        @Bean
        @Qualifier("transactionManager")
        public PlatformTransactionManager transactionManager() {
            return new DataSourceTransactionManager(dataSource());
        }
    
        @Bean
        public com.querydsl.sql.Configuration initConfiguration() {
            // check the spring integration section
        }
    
        @Bean
        public SQLQueryFactory queryFactory() {
            // check the spring integration section
        }
    }
    
    @Repository
    @Transactional
    public class PaymentDAO {
    }
    

    spring integration section

    您还可以在spring上下文xml中声明EnableTransactionManagement
    <tx:annotation-driven transaction-manager="transactionManager" proxy-target-class="true"/>

  2. # 2 楼答案

    我遇到了同样的问题

    问题是QueryDSL希望数据源连接位于事务中。因此,要么您必须显式地开始事务并处理它,要么IOC容器应该为您完成

    在这种情况下,您很可能在任何应用程序层(服务/存储库)中都没有@Transactional注释,而这些应用程序层本应启动事务

    将@Transactional注释添加到dao或服务层以解决此问题

    帮助我的链接是 https://groups.google.com/forum/#!topic/querydsl/_PqMek79TZE

    一个范例项目https://github.com/querydsl/querydsl/tree/master/querydsl-examples/querydsl-example-sql-spring

    更新

    这就是示例项目中DaoImpl的实现方式
    请注意类级别中的@Transactional注释

    @Transactional
    public class CustomerDaoImpl implements CustomerDao {
    
    @Inject
    SQLQueryFactory queryFactory;
    
    final QBean<CustomerAddress> customerAddressBean = bean(CustomerAddress.class,
            customerAddress.addressTypeCode, customerAddress.fromDate, customerAddress.toDate,
            bean(Address.class, address.all()).as("address"));
    
    final QBean<Customer> customerBean = bean(Customer.class,
            customer.id, customer.name,
            bean(Person.class, person.all()).as("contactPerson"),
            GroupBy.set(customerAddressBean).as("addresses"));
    
    @Override
    public Customer findById(long id) {
        List<Customer> customers = findAll(customer.id.eq(id));
        return customers.isEmpty() ? null : customers.get(0);
    }
    
    @Override
    public List<Customer> findAll(Predicate... where) {
        return queryFactory.from(customer)
            .leftJoin(customer.contactPersonFk, person)
            .leftJoin(customer._customer3Fk, customerAddress)
            .leftJoin(customerAddress.addressFk, address)
            .where(where)
            .transform(GroupBy.groupBy(customer.id).list(customerBean));
    }
    
    @Override
    public Customer save(Customer c) {
        Long id = c.getId();
    
        if (id == null) {
            id = queryFactory.insert(customer)
                    .set(customer.name, c.getName())
                    .set(customer.contactPersonId, c.getContactPerson().getId())
                    .executeWithKey(customer.id);
            c.setId(id);
        } else {
            queryFactory.update(customer)
                .set(customer.name, c.getName())
                .set(customer.contactPersonId, c.getContactPerson().getId())
                .where(customer.id.eq(c.getId()))
                .execute();
    
            // delete address rows
            queryFactory.delete(customerAddress)
                .where(customerAddress.customerId.eq(id))
                .execute();
        }
    
        SQLInsertClause insert = queryFactory.insert(customerAddress);
        for (CustomerAddress ca : c.getAddresses()) {
            if (ca.getAddress().getId() == null) {
                ca.getAddress().setId(queryFactory.insert(address)
                    .populate(ca.getAddress())
                    .executeWithKey(address.id));
            }
            insert.set(customerAddress.customerId, id)
                .set(customerAddress.addressId, ca.getAddress().getId())
                .set(customerAddress.addressTypeCode, ca.getAddressTypeCode())
                .set(customerAddress.fromDate, ca.getFromDate())
                .set(customerAddress.toDate, ca.getToDate())
                .addBatch();
        }
        insert.execute();
    
        c.setId(id);
        return c;
    }
    
    @Override
    public long count() {
        return queryFactory.from(customer).fetchCount();
    }
    
    @Override
    public void delete(Customer c) {
        // TODO use combined delete clause
        queryFactory.delete(customerAddress)
            .where(customerAddress.customerId.eq(c.getId()))
            .execute();
    
        queryFactory.delete(customer)
            .where(customer.id.eq(c.getId()))
            .execute();
    }
    
    }
    

    在您的情况下,注释应该放在DatabaseFacade实现中。我假设您的Spring应用程序也配置了事务管理器