html如何使用以下同级在<ul JAVA内部的所有<li>中单击
我可以点击“导师”标签,但我想点击每一个李,从“导师”标签链接开始
<ul _ngcontent-cwp-c18="" class="navigation clearfix">
<li _ngcontent-cwp-c18="" routerlinkactive="current" class=""><a _ngcontent-cwp-c18="" href="#/index">Home</a></li>
<li _ngcontent-cwp-c18=""><a _ngcontent-cwp-c18="" href="https://courses.rahulshettyacademy.com/courses">Courses</a></li>
<li _ngcontent-cwp-c18="" routerlinkactive="current" class="current"><a _ngcontent-cwp-c18="" href="#/mentorship">Mentorship</a></li>
<li _ngcontent-cwp-c18="" routerlinkactive="current"><a _ngcontent-cwp-c18="" href="#/practice-project">Practice Projects</a></li>
<li _ngcontent-cwp-c18="" routerlinkactive="current"><a _ngcontent-cwp-c18="" href="#/consulting">Consulting</a></li>
<li _ngcontent-cwp-c18="" routerlinkactive="current"><a _ngcontent-cwp-c18="" href="#/part-time-jobs">Earn</a></li>
<li _ngcontent-cwp-c18=""><a _ngcontent-cwp-c18="" href="http://www.qaclickacademy.com/blog/">Articles</a></li>
<li _ngcontent-cwp-c18="" routerlinkactive="current"><a _ngcontent-cwp-c18="" href="#/about-my-mission">About</a></li>
<li _ngcontent-cwp-c18="" routerlinkactive="current"><a _ngcontent-cwp-c18="" href="#/contact-us">Contact</a></li>
</ul>
这就是我所尝试的:
driver.get("http://www.qaclickacademy.com/");
driver.findElement(By.xpath("//ul[@class='nav navbar-nav navbar-right']//a[contains(text(),'Interview Guide')]")).click();
//mentorship
driver.findElementByXPath("//div[@class='nav-outer clearfix']//a[contains(text(),'Mentorship')]").click();
//practice projects
driver.findElementByXPath("//div[@class='nav-outer clearfix']//a[contains(text(),'Mentorship')]/following-sibling::li[1]").click();
//consulting
driver.findElementByXPath("//div[@class='nav-outer clearfix']//a[contains(text(),'Mentorship')]/following-sibling::li[2]").click();
//earn
driver.findElementByXPath("//div[@class='nav-outer clearfix']//a[contains(text(),'Mentorship')]/following-sibling::li[3]").click();
请问,我如何使用以下兄弟姐妹点击每一行,从一个特定的开始
# 1 楼答案
首先,您必须找到紧跟在
Mentorship
之后的列表计数,然后您可以迭代一个接一个地单击。编写以下代码,它工作正常# 2 楼答案
您需要选择父项(..)在使用
following-sibling
之前,对a
元素的。您可以使用:或者,更短但更消耗的形式: